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Why parallelogram has no lines of symmetry?
If you draw a diagonal line from corner to corner of a parallelogram, that is a line of symmetry.
How do you figure out the area of a diamond?
Do exactly the same thing for a rhombus or a parallelogram A = base x height (parallelogram) OR A = 1/2 x diagonal 1 x diagonal 2
If one diagonal of a quadrilateral bisects the other when is the quadrilateral a parallelogram?
In this case, the quadrilateral is sometimes a parallelogram.
What quadrilateral has only one diagonal that is bisected?
Any quadrilateral that is not a parallelogram can have only one diagonal that is bisected by the other.
Prove that if the diagonal of a parallelogram does not bisect the angles through the vertices to which the diagonal is drawn the parallelogram is not a rhombus?
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
