If you know the answer please tell me.
If you draw a diagonal line from corner to corner of a parallelogram, that is a line of symmetry.
Do exactly the same thing for a rhombus or a parallelogram A = base x height (parallelogram) OR A = 1/2 x diagonal 1 x diagonal 2
In this case, the quadrilateral is sometimes a parallelogram.
Any quadrilateral that is not a parallelogram can have only one diagonal that is bisected by the other.
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
The height and longer diagonal do not provide enough information to calculate the sides.
two congruent triangles
A parallelogram is anything from a square to a rectangle. As long as it has parallel sides, then it is a parallelogram. If you're thinking of a rhombus, then it has diagonal sides.
a squished rectangle
A parallelogram has two diagonals the same as all 4 sided quadrilaterals
No. Most do not.
If you draw a diagonal line from corner to corner of a parallelogram, that is a line of symmetry.
Either diagonal of a parallelogram divides the parallelogram into two triangles of equal areas. Thus area of triangle abd = half that of the parallelogram abcd. The required ratio is 1 / 2.
Do exactly the same thing for a rhombus or a parallelogram A = base x height (parallelogram) OR A = 1/2 x diagonal 1 x diagonal 2
In this case, the quadrilateral is sometimes a parallelogram.
True
Any quadrilateral that is not a parallelogram can have only one diagonal that is bisected by the other.