sometimes
you can't, because the Pythagorean theorem is for right triangles and the triangles formed by the diagonal of a parallelogram are not right triangles.
Not necessarily. But a parallelogram with perpendicular diagonals must always be one.
False. Every rhombus is a parallelogram, but not every rhombus is a square. Only those that have right angles are squares. Every rhombus is a parallelogram because its diagonal lines are perpendicular, and they bisect an interior angle.
The diagonal is ~16.97 units.
Two congruent triangles.. To prove it, use the SSS Postulate.
In a parallelogram of forces, the resultant force is represented by the diagonal of the parallelogram drawn from the initial point of the forces to the opposite corner. The magnitude and direction of the resultant force are determined by the length and orientation of this diagonal in the parallelogram.
The diagonal of a parallelogram divides it into two congruent triangles. This is because the diagonal creates two pairs of congruent triangles by dividing the parallelogram into two equal halves.
two congruent triangles
A parallelogram is anything from a square to a rectangle. As long as it has parallel sides, then it is a parallelogram. If you're thinking of a rhombus, then it has diagonal sides.
a squished rectangle
A parallelogram has two diagonals the same as all 4 sided quadrilaterals
No. Most do not.
If you know the answer please tell me.
If you draw a diagonal line from corner to corner of a parallelogram, that is a line of symmetry.
Either diagonal of a parallelogram divides the parallelogram into two triangles of equal areas. Thus area of triangle abd = half that of the parallelogram abcd. The required ratio is 1 / 2.
Do exactly the same thing for a rhombus or a parallelogram A = base x height (parallelogram) OR A = 1/2 x diagonal 1 x diagonal 2