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What is the percent uncertainty in the area of a circle whose radius is 1.8 x 104 cm?
There are two ways of answering this questionCalculus Let A denote the area and r the radius.Then A = pi*r2 = pi*1.8*104cm = 1,017,876*103 cm2Now "error" = dA = pi*2r*dr where dr is the error in the measurement of the radius = 0.05*104 = 500 cm.So dA = 56,549*103 cm2.Therefore, percentage error = 100*dA/A = 5.55... (recurring) %Explicit calculationr = 1.8*104 cm. Therefore the range for radius is 17,500 to 18,500 cm.That gives an area of 1,017,876*103 cm2 with a range of962,113*103 to 1,075,210*103 cm2That gives an average absolute error of 56,549*103 cm2 and as before, the percentage error is 5.55... %.
What is a green triangle in Excel?
it means an error in the cell formula. http://www.bestjobsmagazine.com/ -- click to find some jobs
If the actual length is 76.49 cm what is the percent error for the measurement 76.48 cm?
|76.48-76.49|÷76.49=0.013%
A box with a square base has its height twice its width.If the width of the box is 8.5 inches with a possible error of 0.3 inches find the possible error in the volume of the box.?
Area of base lies between 8.2 x 8.2 and 8.8 x 8.8 ie between 67.24 and 77.44. Height between 16.4 and 17.6 so volume lies between 16.4 x 67.24 and 17.6 x 77.44 ie between and 1102.736 and 1362.944 cuinches, a possible error of 260 and a bit cuinches
How do you find the volume of a golf ball?
Knowing the diameter of the ball allows you to calculate it. Using displacement of water allows to directly calculate it. Using direct measurement eliminates the error caused by the "dimples" on the ball's surface. (The minimum legal size for a ball has a volume of about 2.482 cubic inches or 40.68 cm3.)How to computeV = 4/3 (pi) r3 (4 x 3.1416 x radius cubed)How to measureThe easiest way to check would be to put a golf ball in a beaker of water. Fill a 200 ml beaker with water, and place the ball in it. Catch the overflow in another measured beaker. Since water is almost exactly 1 ml = 1 cc, the liquid displaced by the completely submerged ball will provide a close estimate of its volume in cm3.
