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If the actual length is 76.49 cm what is the percent error for the measurement 76.48 cm?
Wiki User
∙ 6y ago
|76.48-76.49|÷76.49=0.013%
Wiki User
∙ 6y ago
Fiona Rosch
0.013%
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When using a protractor a student measure the sum of the interior angles in a triangle and obtain 176 degrees what is the percent error of this measurement?
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Formula of radious given curve length and chord length?
R = radius c = chord length s = curve length c = 2Rsin(s/2R) you can solve for radius by trial and error as this is a transcendental equation
What is the percent error of this measurement if Using a protractor a student measures the sum of the interior angles in a triangle and obtains 176 degrees?
((Result-accepted value)/accepted value) x 100 ((176-180)/180) x 100 = -2.222 180 is the max measure of the sum of the interior angles I just dropped the -
What is the percent uncertainty in the area of a circle whose radius is 1.8 x 104 cm?
There are two ways of answering this questionCalculus Let A denote the area and r the radius.Then A = pi*r2 = pi*1.8*104cm = 1,017,876*103 cm2Now "error" = dA = pi*2r*dr where dr is the error in the measurement of the radius = 0.05*104 = 500 cm.So dA = 56,549*103 cm2.Therefore, percentage error = 100*dA/A = 5.55... (recurring) %Explicit calculationr = 1.8*104 cm. Therefore the range for radius is 17,500 to 18,500 cm.That gives an area of 1,017,876*103 cm2 with a range of962,113*103 to 1,075,210*103 cm2That gives an average absolute error of 56,549*103 cm2 and as before, the percentage error is 5.55... %.
A regular octagon with sides of length 8 and an apothem of length 9.66 has an area of how many square units?
By Apothem LengthThe area of a regular octagon can also be computed using its measured apothem (a line from the center to the middle of any side). The formula for an octagon with side length s and apothem a is Area = a4s . (apothem times one-half the perimeter)So for this example, (8 cm and 9.66 cm) Area = (9.66)(32) = 309.12 cm2----By Side LengthThe area of a regular octagon with side length s is given as Area = 4.828427 s2 , so for a regular octagon of side length 8 cm , the area is calculated as 309.02 cm2. (indicating an error from rounding the apothem length)(This formula is generated by adding or subtracting the missing corner triangles.)
What is the percentage error of a length measurement of 0.229 cm if the correct value is 0.225 cm?
What is the percent error of a estimated measurement of 0.229 cm if the actual value is 0.225 cm?
When an error of 1 percent is made in the length of a square the percentage of error in the area of a square will be?
area= side^2 let the symbol # denote error in measurement #area/area= 2(#length/length) #area/area*100= 2(#length/length)*100 percent error in area= 2*percent error in length=2% 2 per cent
Which property of a measurement is best estimated from the percent error?
Measurement error: obviously!
Percent error formula?
Divide the calculated or estimated error by the magnitude of the measurement. Take the absolute value of the result, that is, if it is negative, convert to positive. This would make the percent error = | error / measurement |.
How do you calculate the mean absolute percent error with a 0 actual value?
By definition of percent error, you can't. But you can approximate zero instead, with the number of decimals appropriate to the accuracy of the measurement, e.g. 0.01, 1E-100, etc.
When an error of 1 percent is made in the length of a square error is?
The error in its area is then 2 percent....
What is a percent error?
It is a measure measurement of the amount of error made in an experiment. It is obtained by comparing the actual result, with the result gotten from the experiment. % error = [(experimental value - true value) / true value] x 100
When an error of 1 percent is made in the length of a square the percentage error in the area of square will be?
The percentage error in the area of the square will be twice the percentage error in the length of the square. This is because the error in the length affects both the length and width of the square, resulting in a compounded effect on the area. Therefore, if there is a 1 percent error in the length, the percentage error in the area would be 2 percent.
What makes your percent error calculated value not equal to the actual value?
You do not add the percentage error but the actual error.
A student measured the mass of an object and found it to be 658 grams. The actual objects mass is known to be 755 grams what is the percent error of the measurement?
It is approx 12.8%.
How do accuracy and precision of measurement affect calculated values and percent error?
The more precise your instruments of measurement are, the less percentage of error you will have.
What is the percent error of 4cm?
A percent error depends on the size of the measurement as well as the error itself. It's very intuitive to think about: If you're measuring a piece of paper and you're off by 4 cm, you'll have problems; if you're measuring the moon, that's nothing. A bigger percent error is a bigger deal to an engineer. You can calculate it the same way as any percentage: Divide the error by the total length of the measurement, then multiply by 100 to convert it from a proportion to a percentage.
