Formula: S = 2B + L
The surface area of a cylinder prism has round shape and the surface of a rectangular prism has a square shape.
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Suppose that the area of the rectangular base is: lw then if the height is: h the surface area is: lw + lh + wh I believe that formula is for the surface area of a rectangular prism...
No.
To find the surface area of a rectangular prism, you need to calculate the area of each of the six faces and then sum them up. The formula for the surface area of a rectangular prism is 2lw + 2lh + 2wh, where l is the length, w is the width, and h is the height. Given the dimensions of 7 cm, 4 cm, and 2 cm for the length, width, and height respectively, you can plug these values into the formula to find the surface area.
Surface area = 2ab + 2bc + 2ac
The surface area of a cylinder prism has round shape and the surface of a rectangular prism has a square shape.
The surface area of a rectangular prism can be calculated by adding the areas of all six faces. The formula for the surface area of a rectangular prism is 2lw + 2lh + 2wh, where l, w, and h represent the length, width, and height of the prism, respectively. This formula accounts for the two faces of each dimension (length, width, and height) on the rectangular prism.
Assuming you mean a rectangular prism, you get the smallest surface area if the prism is a cube. You can calculate the required length of side to get that volume; then, based on that, the corresponding surface area.
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LxWx2
Squared. When you find surface area, you are only finding the area of the shapes that make up the three-denominational shape.
I am not sure that a rectangular prism is in any position to care!
Suppose that the area of the rectangular base is: lw then if the height is: h the surface area is: lw + lh + wh I believe that formula is for the surface area of a rectangular prism...
Given the surface area of a rectangular prism, there are infinitely many rectangular prisms possible.
For the same base dimensions (base area) and the same height, the rectangular prism has more surface area.
No.