Width x Length for every face of the figure. Then add them all up.
A(5) = 4 25
You multiply the length and the width of the room
If you know the dimensions of the missing triangle, then compute the area from those dimensions, then subtract that answer from the area of the full rectangle.
Kinda of a combination of both. The surface of a 3-D object is called surface area.
surface area is basically the total area of each surface of the 3d object. Sa = 2-D A = 3-D
find surface area
Write a c program to compute the surface area and volume of a cube
To calculate the surface area of a rectangular prism, you can use the formula: Surface Area = 2(lw + lh + wh), where l is the length, w is the width, and h is the height. You need the dimensions of the prism to compute the exact surface area. If you provide those dimensions, I can help you calculate it!
You can't, you need either the total surface area or the total volume.
A(5) = 4 25
To find the surface area of a rectangular prism, use the formula ( SA = 2lw + 2lh + 2wh ), where ( l ) is the length, ( w ) is the width, and ( h ) is the height of the prism. This formula calculates the area of all six rectangular faces. Simply plug in the dimensions of the prism to compute the total surface area.
Ask your doctor or pharmacist.
creat a flowchart that will compute for the area and perimeter of a square?
You multiply the length and the width of the room
To find the ratio of a solid's surface area, first calculate the surface area of the solid using the appropriate formula based on its shape (e.g., ( 6a^2 ) for a cube, ( 2\pi r(r + h) ) for a cylinder). Then, if comparing two solids, compute their surface areas separately and form the ratio by dividing one surface area by the other. Simplify the ratio if necessary to express it in the simplest form. This ratio provides insight into how the surface areas of the two solids relate to each other.
{A program to compute the area of a triangle} {by Ogboin W. Meshach} Var; b,h:real; BEGIN Writeln('Triangle'); Write('Base: '); Readln(base); Write('Height: '); Readln(height); area:=0.5*base*height; Writeln('Area: ', area :0:2); End.
(base x height) / (n+1)