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Put the equation in the form ax2 + bx + c = 0. Replace a, b, and c in the quadratic formula: x = (-b (plus-or-minus) root(b2 - 4ac)) / 2a. Look at the term under the radical sign, which I wrote as "root" here. If b2 - 4ac is...
- Positive: the equation has two real solutions.
- Zero: the equation has one ("double") solution.
- Negative: the equation has two complex solutions (and therefore no real solution).
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How many solution will there be if the quadratic equation does not touch or cross the x-axis?
0 real solutions. There are other solutions in the complex planes (with i, the imaginary number), but there are no real solutions.
What does coefficients of a quadratic equation mean?
A coefficient is the number before the variable (e.g. the 3 in 3x, or the 22 in 22x^2). For example, in the following quadratic equation, the coefficient to x is 4, and the coefficient to y is 12. 4x^2+12y+4 Remember that a number preceded by a ^ is a power, i.e 4x^2 is 4x squared.
Can you solve a quadratic equation by completing the square even though it is not a perfect square?
Yes, it won't be exact, but you can round the number to get a close estimate.
How many sides does a polygon have if it has 902 diagonals?
Let n be the number of sides: 1/2*(n2-3n) = diagonals 1/2*(n2-3n) = 902 Multiply both sides by 2 and form a quadratic equation: n2-3n-1804 = 0 Solving the above by means of the quadratic equation formula gives a positive value for n as 44 Therefore the polygon has 44 sides
A polygon has 14 diagonals how many sides does it have?
To determine the number of sides in a polygon with 14 diagonals, we can use the formula for the number of diagonals in a polygon: D = n(n-3)/2, where n is the number of sides. By setting D = 14 and solving for n, we get n(n-3)/2 = 14. Simplifying this equation, we find that n^2 - 3n - 28 = 0. Factoring this quadratic equation, we get (n-7)(n+4) = 0. Therefore, the polygon has either 7 or -4 sides. Since the number of sides cannot be negative, the polygon must have 7 sides.
