Divide square into 4parts gets 4 rhombus shapes
You will need to divide the shaded area into smaller parts, such as triangles or rectangles, or find the length of sides of these polygons.
You can divide the square from a point halfway between two of the corners to a similar point on the opposite side, to produce to rectangles. You can do this vertically or horizontally, but the result is the same. The second method is to divide the square from one corner to the corner directly opposite to it, in effect dividing the square into two triangles.
To divide a square in half four different ways, you can draw two diagonals intersecting at the center, creating four equal triangles. Another way is to draw a horizontal line passing through the center of the square, dividing it into two equal rectangles. You can also draw a vertical line through the center to create two more equal rectangles. Lastly, you can divide the square into four smaller squares by drawing two perpendicular lines through the center.
3R1
Cut it into 3 rectangles.
no,we can divide the figure into squares,rectangles and triangles
You can't.
If you draw your triangles using the centre of the circle as one vertex and two more on the circumference, the area of the circle is approximately equal to the sum of the areas of the triangles; the smaller you make the triangles, the more accurate your result will be.
One method is to divide it into regular shapes - rectangles, triangles, etc. - and measure the areas of those shapes.
You divide the shape into smaller shapes you can calculate, like rectangles and triangles. If the shape is irregular, you have to approximate, for example by dividing it into many narrow rectangles. This technique is called "integration".
You will need to divide the shaded area into smaller parts, such as triangles or rectangles, or find the length of sides of these polygons.
you can't have circumference with a square. if the have the perimeter(the distance around it) you divide it by four then multiply it by two. this only works with squares, not rectangles.
You can divide the square from a point halfway between two of the corners to a similar point on the opposite side, to produce to rectangles. You can do this vertically or horizontally, but the result is the same. The second method is to divide the square from one corner to the corner directly opposite to it, in effect dividing the square into two triangles.
Not really, but that depends on what your definition of easy is. Try to divide the irregular quadrilateral into smaller regular pieces -- triangles and squares. You should be able to divide the shape into one square and two triangles. Then you can determine their areas and find the sum.
Draw diagonal lines to form a diagonal cross in each square, so dividing all the squares into four triangles in each. A pencil and a straightedge is all that is needed, no measuring to form vertical and horizontal lines to divide each square into four smaller squares is required. Can't show a photo or graphics in Answers, I believe.
Given P = Prime number then you can build (P-1)/2 number of rectangles given any prime number. All prime numbers are odd and you would need two squares to make a rectangle. Given that you need two squares to build a rectangle, you divide your prime number by two to get the number of "pairs" of squares and thus the number of rectangles you can build. Since the number 2 does not divide evenly into an odd number - all prime numbers are odd - then you either subtract one from the prime number before dividing or discard the remainder if you choose not to subtract one before dividing.
Rectangles are related to the distributive property because you can divide a rectangle into smaller rectangles. The sum of the areas of the smaller rectangles will equal the area of the larger rectangle.