You draw an angle and its vertex should be A on its left B and on its right C. ( An Acute)
Confirmed
The answer will depend on what tools or instruments you may use.
It is easiest to draw it using two right angled triangles.Draw a line AB that is 2 units long. From B, draw BC which is perpendicular to AB and 2 units long. Join AC. From C, draw CD which is perpendicular to AC (clockwise if BC is clockwise from AB, or anticlockwise if BC is anticlockwise) and make CD 2 uinits long. Then AD is a line segment which is sqrt(12) units long.
Line BA
Place the point if the compass on point B and draw an arc across AB.
line r
Draw and label line Ab
line AB intersects plane Q at W
The answer will depend on what tools or instruments you may use.
First, it needs to be a line segment: a line is infinitely long and so has no midpoint.Suppose the line to be bisected is AB. Place the point of a pair of compasses at A with an arc which is greater than half AB. Draw arcs above and below the line segment. Then, move the compass point to B and without changing the arc width, draw fresh arcs to intercept the previous ones at points X and Y. The intersection of the line segment XY and AB is the midpoint of AB.
Honey, lines AB and BA are like two peas in a pod - they're the same darn thing! In geometry, the order of the points on a line doesn't matter, so whether you call it line AB or line BA, it's all just one straight shot from point A to point B. So, yes, line AB is indeed the same as line BA.
line segment, line ab, __ ab
It is easiest to draw it using two right angled triangles.Draw a line AB that is 2 units long. From B, draw BC which is perpendicular to AB and 2 units long. Join AC. From C, draw CD which is perpendicular to AC (clockwise if BC is clockwise from AB, or anticlockwise if BC is anticlockwise) and make CD 2 uinits long. Then AD is a line segment which is sqrt(12) units long.
Let's assume the triangle has points A, B, and C. Method 1 (3 lines) Draw two lines across the triangle parallel to line segment AB. Now you have two trapezoids and one triangle. Draw another line from C to the any point on the closest of the two lines you just drew, splitting the triangle into two more triangles. Method 2 (2 lines) Draw one line across the triangle parallel to line segment AB. Now you have one trapezoid and one triangle. Draw a second line that passes through C and is perpendicular to AB, splitting the trapezoid into two trapezoids and the triangle into 2 triangles. Method 3 (3 lines) Draw one line from point C to any point on line segment AB. Then draw a line parallel to AC and one parallel to BC, but don't let them cross the line you just drew.
The perpendicular bisector of a line segment AB is the straight line perpendicular to AB through the midpoint of AB.
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Line BA
Draw a straight line AB of any length x. Draw another line, parallel to AB and at a distance of 2*24/x units from it. Select any point on the second line and call that point C. Join AC and BC. Then triangle ABC will have an area of 24 square units.