It is easiest to draw it using two right angled triangles.
Draw a line AB that is 2 units long. From B, draw BC which is perpendicular to AB and 2 units long. Join AC. From C, draw CD which is perpendicular to AC (clockwise if BC is clockwise from AB, or anticlockwise if BC is anticlockwise) and make CD 2 uinits long. Then AD is a line segment which is sqrt(12) units long.
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A square with an area of 144cm2 has sides of 12cm which is the square root of 144cm. 12cm x 12cm gives 144cm2.
The formula is the square root of: (x2-x1)^2 plus (y2-y1)^2
Using Pythagoras; theorem it is 12 times square root of 2 which is about 17 cm rounded to the nearest integer
The length of segment AB (A(2,6), B(0,3)) and CD (C(-1,0), D(1,3)) is the square-root of 13. The two segments are congruent.
From point A to point B You need the X and Y value of both point A and B Formula = Distance = Square root of [(x1 + x2)2 + (y1 + y2)2] So therefore given points (1:2) and (5:-6) Square root of (1 - 5)squared + (2 + 6)squared =Square root of -4 squared + 8 squared =Square root of 16 + 64 =Square root of 80 This can be your answer but you should go a step further =Square root of 80 =Square root of 16 * 5 =4*Square root of 5