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It is easiest to draw it using two right angled triangles.
Draw a line AB that is 2 units long. From B, draw BC which is perpendicular to AB and 2 units long. Join AC. From C, draw CD which is perpendicular to AC (clockwise if BC is clockwise from AB, or anticlockwise if BC is anticlockwise) and make CD 2 uinits long. Then AD is a line segment which is sqrt(12) units long.
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Find the measure of one side of a square whose area is 144 cm2?
A square with an area of 144cm2 has sides of 12cm which is the square root of 144cm. 12cm x 12cm gives 144cm2.
How can you find the length of a line segment in the coordinate plane?
The formula is the square root of: (x2-x1)^2 plus (y2-y1)^2
What is the length of a diagonal of square whose side measures 12cm?
Using Pythagoras; theorem it is 12 times square root of 2 which is about 17 cm rounded to the nearest integer
Find the length of each segment tell whether the segments are congruent?
The length of segment AB (A(2,6), B(0,3)) and CD (C(-1,0), D(1,3)) is the square-root of 13. The two segments are congruent.
How do you figure out the length of a line on a graph?
From point A to point B You need the X and Y value of both point A and B Formula = Distance = Square root of [(x1 + x2)2 + (y1 + y2)2] So therefore given points (1:2) and (5:-6) Square root of (1 - 5)squared + (2 + 6)squared =Square root of -4 squared + 8 squared =Square root of 16 + 64 =Square root of 80 This can be your answer but you should go a step further =Square root of 80 =Square root of 16 * 5 =4*Square root of 5
