This is a quadratic equation, and so you it falls under the rule: ax squared + bx + c. This means you need to times the 2x squared by 15, which is 30. Then you need to find the factors of thirty, i.e. 3 and 10, 15 and 2, 5 and 6. You need to find the pair of factors that add to make -13x, which would be -3 and -10. you then need to put these into the equation - it would become 2x squared -10x (as one equation) and -3x +15 would be another equation. we can see that 2x squared and -10x have 2x in common, and so the answer for that would be 2x (x - 5). the second equation would be -3 (x - 5). the two equations have x - 5 in common, and that would make up the first set of brackets. you then add the rest (2x - 3) and your answer would be (x - 5) (2x - 3).
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. There is no sign before 36. However, assuming the missing sign is a plus, the roots are 4 and 9.
Y=13/11x + 12/11
It is x^2 -13x +12 = (x-1)(x-12) when factored
(x-4)
6x^2 -13x+6 = (3x-2)(2x-3) when factorized
-6 = 3 x -2 13 = 5 x 3 - 2 → 5x² + 13x - 6 = (5x - 2)(x + 3)
(x - 3)(2x - 7)
(13x^2 - 4y)(2x^2 - 5y)
It is (2x-5)(x-4) when factored
13X squared + 7X + 12
x^2 - 13x + 36 = 0 Factor: (X-9)(X-4) = 0 X = 9 X = 4
(13x + 39)(x + 2) * * * * * Don't you think it might, instead, be (13x - 39)(x - 2)? Multiply it out, and see!
2x2+13x+15 = (2x+3)(x+5)
Multiply all terms by 10 it then becomes 10x2+13x+4 = (5x+4)(2x+1) when factored.