y = {slope}x + {y intercept}
-7
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
If you mean y = 3x then the slope is 3 and there is no y intercept
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
A straight line in slope-intercept format has the equation: y = mx + b Where m is the slope, b the y-intercept. So, all you have to do is copy this equation, then replace "m" by the given slope, and "b" by the given y-intercept.
The equation for the given points is y = x+4 in slope intercept form
Y=mc+b
An equation in slope intercept form is given by y = mx + b, where m is the slope and b is the y-intercept.Examples:If the slope is 3 and the y- intercept is 4, the equation will be, y = 3x + 4If the slope is -1/5 and y-intercept is -2/3, the equation will be, y = -1/2)x - 2/3
y = mx + b, where m is the slope and b is the y-intercept.
The equation of a line in slope-intercept form is given by y = mx + b, where "m" represents the slope of the line and "b" represents the y-intercept.
y = {slope}x + {y intercept}
Slope = 0, intercept = 3
As for example if the slope is 3 and the y intercept is 6 then the equation is: y=3x+6
-7
There is no y-intercept or slope for this given equation, because its graph is a vertical line perpendicular to the x-axis.