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∙ 12y agoy = mx + b, where m is the slope and b is the y-intercept.
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∙ 12y agoY=mc+b
As for example if the slope is 3 and the y intercept is 6 then the equation is: y=3x+6
Slope Intercept form is meant for a line, so if you know the slope m in the equation y=mx+b then with a given point say (3,4) and say the slope of the line was 2 then the equation would read y=2x+4.
slope-intercept from is y=mx+b, m is the slope and b is the y-intercept. put the values of the slope and y-intercept into the equation. y=2x-2
The given equation is : x + 5 + y = 0 Write in standard form of equation of straight line : y = mx + c . Where m is slope and c is y-intercept. We get: y = -x - 5 Which gives slope = -1 y-intercept = -5 To get x-intercept put y = 0 in the equation. We get x-intercept = -5
Y=mc+b
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
As for example if the slope is 3 and the y intercept is 6 then the equation is: y=3x+6
An equation in slope intercept form is given by y = mx + b, where m is the slope and b is the y-intercept.Examples:If the slope is 3 and the y- intercept is 4, the equation will be, y = 3x + 4If the slope is -1/5 and y-intercept is -2/3, the equation will be, y = -1/2)x - 2/3
-7
y= slope + y-intercept
y = 3x/4 + 7
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
Slope Intercept form is meant for a line, so if you know the slope m in the equation y=mx+b then with a given point say (3,4) and say the slope of the line was 2 then the equation would read y=2x+4.
-12
The slope intercept form of the equation of a line is: y = mx + b The general form is: Ax + By + C = 0 So, when the line is given in the slope intercept form, the general form will be mx - y + b = 0
The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.