You do not need to know the length of the diagonals to find the area of a kite.
A kite is essentially four triangles combined, so you just find the area of the four individual triangles and add them together.
In actuality, the two triangles that make up the top of the kite form a mathematical rectangle, as do the two triangles that comprise the bottom, because the formula for finding the area of a triangle is simply taking one-half the area of the rectangle that would be formed by the legs of the triangle, and two times one-half equals one whole.
Let's look at a kite and the formula. For the sake of this example we'll say that a kite is composed of a vertical and a horizontal member, which intersect at some point. The horizontal member is bisected (intersected in the middle) While the vertical member can be intersected at any number of points depending on the design of the kite. Typically, the vertical member will be intersected closer to the top to achieve the classic kite configuration.
On our kite we will call the length of the vertical member above the intersection of the two kite sticks "a", the length of the vertical section below the intersection "b" and the length of the horizontal stick on either side of the intersection "c". Our formula for the area of the kite now becomes:
1/2(a X c) + 1/2(a X c) + 1/2(b X c) + 1/2(b X c)
Which in reality (simpler terms) is:
(a X c) + (b X c)
To plug in some numbers, let's take two kite sticks, the vertical stick being 4' long, the horizontal stick 2.5' long. The intersection of the sticks leaves 2.5' for the bottom section of the vertical and 1.5' for the upper section of the vertical. The horizontal stick is cut in half, or 1.25' on each side of the intersection. Our area then is:
(1.5 X 1.25) + (2.5 X 1.25) = 1.875 + 3.125 = 5 square feet.
As you can see, the length of the diagonals never entered into our equation.
Multiply the diagonals and divide by 2. So : 18 x 7 = 126 126 / 2 = 63 ft
Yes 1 of the diagonals of a kite is symmetrical
No, the diagonals are not equal.
Yes the diagonals of a kite bisect each other at 90 degrees.
A kite is called a quadrilateral that has two adjacent sides of equal length and the other two sides of equal in length. If the kite ABCD has AB = AD and CB = CD, then diagonals AC and BD are perpendiculars and AC bisects BD. Let AC = 28 ft, and BD = 13 ft. Let say that the two diagonals intersect each other at the point E. In the kite ABCD, we have two congruent triangle, the triangle ABC and the triangle ADC, where the diagonal AC is the common base, BE and DE are their altitudes. Since AC bisect BD, we are able to find the area of the kite, which is equal to 2 times the area of one of these congruent triangles. Let's find it: Area of the triangle ABC: AC = 28 ft and BE = 6.5 ft (13/2) A = (1/2)(AC)(BE) = (1/2)(28)(6.5) = 91 ft^2 Thus the area of the kite is 182 ft^2 (2 x 91).
A=1/2d1d2
The area of a quadrilateral kite is 0.5 times the product of its diagonals.
product of diagonals/2
Area of a kite in square units = 0.5 times the product of its diagonals
Multiply the two 'diagonals' and divide by 2. See related link.
A Hexagonal Kite can be deduced to a rectangle of an area equal to 0.75 Kite diagonals * sqrt (3/4) Kite diagonals = 400 square meters. Therefore, diagonal = sqrt ( 400 / ( 3/4 * sqrt(3/4) ) ) meters =~ 24.816 meters
Area of a kite in square units = 0.5 times the product of its diagonals
Multiply the diagonals and divide by 2. So : 18 x 7 = 126 126 / 2 = 63 ft
Yes 1 of the diagonals of a kite is symmetrical
No, the diagonals are not equal.
1) Diagonals intersect at right angles. 2) The diagonal bisecting the angle between the two longer sides also bisects the other diagonal. 3 The area of a kite = the product of both diagonals ÷ 2.
Because in both cases their diagonals cross at right angles So their areas are: 0.5*product of diagonals