guess where it would go...
shouldnt be cheating on your study island:)
i think that the range and the domain of a parabola is the coordinates of the vertex
The vertex of a triangle is the point where two or more sides of the triangle intersect. In the case of triangle TIF, the vertex would be the point where the sides TI and IF intersect. To determine the exact coordinates of the vertex, you would need the coordinates of points T, I, and F and then use the equations of the lines containing the sides to find their point of intersection.
The coordinates will be at the point of the turn the parabola which is its vertex.
The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.
dont no stuck on iyt help dont no stuck on iyt help
To determine the coordinates of the preimage of vertex M, I would need additional information about the transformation that was applied to vertex M, such as the type of transformation (e.g., translation, rotation, reflection, scaling) and the coordinates of M itself. If you provide the coordinates of M and the details of the transformation, I can help you find the preimage coordinates.
i think that the range and the domain of a parabola is the coordinates of the vertex
To determine the coordinates of the vertex of a quadratic function in the form (y = ax^2 + bx + c), you can use the vertex formula (x = -\frac{b}{2a}) to find the x-coordinate. Once you have the x-coordinate, substitute it back into the original equation to find the corresponding y-coordinate. Thus, the vertex coordinates are ((-\frac{b}{2a}, f(-\frac{b}{2a}))). For a parabola, this point represents either the maximum or minimum value, depending on the sign of (a).
It depends on what the coordinates of the first three vertices are!
The vertex is at the origin of coordinates ... the point (0, 0).
The vertex of a triangle is the point where two or more sides of the triangle intersect. In the case of triangle TIF, the vertex would be the point where the sides TI and IF intersect. To determine the exact coordinates of the vertex, you would need the coordinates of points T, I, and F and then use the equations of the lines containing the sides to find their point of intersection.
Use this form: y= a(x-h)² + k ; plug in the x and y coordinates of the vertex into (h,k) and then the other point coordinates into (x,y) and solve for a.
To determine the coordinates of the fourth vertex of a rectangle, you need to know the coordinates of the other three vertices. If you have the coordinates of three vertices, you can find the fourth by using the properties of a rectangle, where opposite sides are equal and the diagonals bisect each other. For example, if the vertices are A(x1, y1), B(x2, y2), and C(x3, y3), you can find the fourth vertex D(x4, y4) through the midpoint formula or by ensuring that the lengths of the sides and the diagonals are consistent. Please provide the coordinates of the existing vertices for a specific answer.
The coordinates will be at the point of the turn the parabola which is its vertex.
Find the midpoint of the two diagonals
Use the equation: (Y-k)^2 = 4a(X-h)
To find the vertex of the quadratic equation ( y = 3x^2 - 12x - 5 ), we can use the vertex formula ( x = -\frac{b}{2a} ), where ( a = 3 ) and ( b = -12 ). Plugging in the values, we get ( x = -\frac{-12}{2 \cdot 3} = 2 ). To find the corresponding ( y )-coordinate, substitute ( x = 2 ) back into the equation: ( y = 3(2)^2 - 12(2) - 5 = -29 ). Thus, the coordinates of the vertex are ( (2, -29) ).