i think that the range and the domain of a parabola is the coordinates of the vertex
The vertex of a triangle is the point where two or more sides of the triangle intersect. In the case of triangle TIF, the vertex would be the point where the sides TI and IF intersect. To determine the exact coordinates of the vertex, you would need the coordinates of points T, I, and F and then use the equations of the lines containing the sides to find their point of intersection.
The coordinates will be at the point of the turn the parabola which is its vertex.
The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.
dont no stuck on iyt help dont no stuck on iyt help
i think that the range and the domain of a parabola is the coordinates of the vertex
It depends on what the coordinates of the first three vertices are!
The vertex is at the origin of coordinates ... the point (0, 0).
The vertex of a triangle is the point where two or more sides of the triangle intersect. In the case of triangle TIF, the vertex would be the point where the sides TI and IF intersect. To determine the exact coordinates of the vertex, you would need the coordinates of points T, I, and F and then use the equations of the lines containing the sides to find their point of intersection.
Use this form: y= a(x-h)² + k ; plug in the x and y coordinates of the vertex into (h,k) and then the other point coordinates into (x,y) and solve for a.
The coordinates will be at the point of the turn the parabola which is its vertex.
Find the midpoint of the two diagonals
Use the equation: (Y-k)^2 = 4a(X-h)
We will be able to identify the answer if we have the equation. We can only check on the coordinates from the given vertex.
The vertex is at (5, -5).
It is (-1, 3).
Suppose a quadrilateral is given using its vertex coordinates. It will be a triangle if three vertices are collinear, that is are on the same line.