guess where it would go...
shouldnt be cheating on your study island:)
i think that the range and the domain of a parabola is the coordinates of the vertex
The coordinates will be at the point of the turn the parabola which is its vertex.
The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.
dont no stuck on iyt help dont no stuck on iyt help
how do you find distance between points
i think that the range and the domain of a parabola is the coordinates of the vertex
It depends on what the coordinates of the first three vertices are!
The vertex is at the origin of coordinates ... the point (0, 0).
Use this form: y= a(x-h)² + k ; plug in the x and y coordinates of the vertex into (h,k) and then the other point coordinates into (x,y) and solve for a.
The coordinates will be at the point of the turn the parabola which is its vertex.
Find the midpoint of the two diagonals
Use the equation: (Y-k)^2 = 4a(X-h)
We will be able to identify the answer if we have the equation. We can only check on the coordinates from the given vertex.
The vertex is at (5, -5).
It is (-1, 3).
Suppose a quadrilateral is given using its vertex coordinates. It will be a triangle if three vertices are collinear, that is are on the same line.
2