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Suppose a polygon has n vertices (and sides). From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex. Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals. number of diagonals = n(n-3)/2

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WHAT IS THE ANSWER TOD12N(N-3) GIVES THE NUMBER OF DIAGONALS d FOR A POLYGON WITH N SIDES.. use THIS EQUATION TO FIND THE NUMBER OF DIAGONALS FOR POLYGON THAT HAS 13 SIDES .SOLVE?

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