It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
nope.aviImproved Answer:-33 because 1/2*(332-99) = 495
The formula to calculate the number of diagonals in a polygon is n(n-3)/2, where n represents the number of vertices. Setting this formula equal to 560 and solving for n, we get n(n-3)/2 = 560. By solving this quadratic equation, we find that the polygon has 20 vertices.
The formula for the number of diagonals in a polygon is s*(s-1)/2 - s To find such a polygon, we solve for when that formula equals s s*(s-1)/2 - s = s s*(s-1)/2 = 2s (s-1)/2 = 2 s-1 = 4 s = 5 Thus, the polygon with this property is the pentagon.
The formula for the sum of the angles of an interior polygon is 180(n-2), where n is the number of sides, so then you solve 180(n-2) = 1980. (n-2) = 11 n = 13. So the polygon has 13 sides.
The formula for the sum of the angles of an interior polygon is 180(n-2), where n is the number of sides, so then you solve 180(n-2) = 1980. (n-2) = 11 n = 13. So the polygon has 13 sides.
1/2*(n2-3n) = number of diagonals Rearranging the formula: n2-3n-(2*diagonals) = 0 Solve as a quadratic equation and taking the positive value of n as the number of sides.
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nope.aviImproved Answer:-33 because 1/2*(332-99) = 495
The formula to calculate the number of diagonals in a polygon is n(n-3)/2, where n represents the number of vertices. Setting this formula equal to 560 and solving for n, we get n(n-3)/2 = 560. By solving this quadratic equation, we find that the polygon has 20 vertices.
Your question is quite confusing because you used the phrase 'two polygon'. When asking mathematical or geometrical questions about shapes you ask about a single specific thing . I assume you meant to ask, '----number of sides of various different polygons, given the number of diagonals in each of them.' I have been drawing polygons with 5 and 6 and 7 and 8 sides and discovering the number of diagonals which can be drawn inside each of them , does not seem to follow a simple formula. I will look into it further and see if I can post you an answer in a day or two. Very interesting question I must say. Hope I can solve it .Additional Information:-The diagonal formula for any polygon is: 1/2*(n2-3n) = number of diagonalsRearrange the formula into a quadratic equation and solve it for a positive value which will be the number of the sides of the given polygon
The formula for the number of diagonals in a polygon is s*(s-1)/2 - s To find such a polygon, we solve for when that formula equals s s*(s-1)/2 - s = s s*(s-1)/2 = 2s (s-1)/2 = 2 s-1 = 4 s = 5 Thus, the polygon with this property is the pentagon.
A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.
the formula for the total number of degrees in a polygon is (x=number of sides) (x-2)180=total degree measure and you divide that number by x to get each angle measure of a regular polygon. so ((x-2)180)/x=30 solve for x and you get x=2.4 you can't have 2.4 sides in a polygon. so no, a regular polygon can't have an interior angle of 30 degrees
The formula for the sum of the angles of an interior polygon is 180(n-2), where n is the number of sides, so then you solve 180(n-2) = 1980. (n-2) = 11 n = 13. So the polygon has 13 sides.
all verticals, horazontals and diagonals must add up to one common number
Suppose the polygon has n sides. Then n*(n-3)/2 = 54 or n*(n-3) = 108 and so, by inspection, n = 12 or you can multiply out the brackets and solve the quadratic equation in n.
The answer depends on what you mean by "solve" a polygon. Do you want to find the number of sides or vertices, or lengths of sides, or measures of angles, or their sum, or the area of the polygon or its perimeter? And the answer, in most cases, will depend on what information you do have.The answer depends on what you mean by "solve" a polygon. Do you want to find the number of sides or vertices, or lengths of sides, or measures of angles, or their sum, or the area of the polygon or its perimeter? And the answer, in most cases, will depend on what information you do have.The answer depends on what you mean by "solve" a polygon. Do you want to find the number of sides or vertices, or lengths of sides, or measures of angles, or their sum, or the area of the polygon or its perimeter? And the answer, in most cases, will depend on what information you do have.The answer depends on what you mean by "solve" a polygon. Do you want to find the number of sides or vertices, or lengths of sides, or measures of angles, or their sum, or the area of the polygon or its perimeter? And the answer, in most cases, will depend on what information you do have.