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If the octagon at the base is regular, the side of the octagon is s and the height of the prism is h, the area of each octagonal base (Ab) is

Ab = 2(√2 +1) s2

The perimeter of the octagon is

P = 8s

Then the surface area of the prism is

As = 2 Ab + Ph

The volume of the prism is

V = Ab h

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