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Remember the Trig. Functions.
Sin(Angle) = opposite / hypotenuse.
Hence algebraically rearranging.
hypotenuse = opposite / [Sin(angle))
NB You MUST know the length of the 'opposite', and the size of the angle.
So if the opposite is of length '2' and the angle is 30 degrees.
Then substituting ;=
hypotenuse = 2 / Sin(30)
From Tables or calculator 'Sin(30) = 1/2 = 0.5'
Hence
hypotenuse = 2 / (1/2) or 2/(0.5)
2/(1/2) = 4 or 2/0.5 = 4
Hence the hypotenuse is '4' units in length.
What else can I help you with?
How are side angle side triangles and Hypotenuse leg alike?
"Hypotenuse-leg" is not necessarily the right-triangle version of "side-angle-side". It's the right-triangle version of "side-side-side", because if you know that it's a right triangle, and you know the hypotenuse and a leg, then you can calculate the length of the other leg. If you want to work with "side-angle-side", and you know the hypotenuse and a leg, then you can find the angle between them, because it's the angle whose cosine is (the known leg) divided by (the hypotenuse), and you can look it up.
How do you solve a 30-60-90 degree?
To solve a 30-60-90 triangle, you need to know the length of one side. The hypotenuse is twice as long as the shortest leg (the side opposite the 30 angle) The longer leg (opposite the 60 angle) is the length of the shorter leg times the square root of 3. So in summary: If you know the hypotenuse, divide it by 2 to find the shorter leg, and multiply that times the square root of 3 to find the longer leg. If you know the longer leg, divide it by the square root of 3 to find the shorter leg, then multiply that by 2 to find the hypotenuse. If you know the shorter leg, multiply it by 2 to find the hypotenuse. Multiply the shorter leg length by the square root of 3 to find the longer leg.
How do you find another leg in Pythagorean theorem with the hypotenuse given?
The square of the hypotenuse minus the square of the leg you know will give you the square of the unknown leg.
How do you find the hypotenuse with only a leg and a degree?
It depends on the position of the 'leg' compared to the known angle. If the 'leg' makes up one of the two sides of the angle, then the other side of the angle is the hypotenuse. In this case the 'leg' would be referred to as the 'adjacent' side. The side the doesn't form part of the angle is referred to as the 'opposite' side. So using the trig. functions. Sin(angle) = opposite / hypotenuse. Then algebraically rearranging hypotenuse = opposite / Sin(angle). Similarly for 'Cos'. Cos(angle) = adjacent/ hypotenuse Hence Hypotenuse = adjacent / Cos(angle) So as an example If the leg/opposite is 2 units. and the angle 30 degrees. Then hypotenuse = 2 / Sin(30). On you calculator you should be find the Sin( 30) = 1/2 = 0.5 Substitute in hypotenuse = 2 / 1/2 ( That is '2' divided by '1/2'), (Division of fractions). hypotenuse = 2 X 2/1 = 4/1 = 4 units. NB When using your calculator to find 'Sin' , 'Cos', and 'Tan' of angles, you will read out some 'horrible' decimal numbers. NNB Do NOT use the TAN(gent) function to find hypotenuse. It is NOT part of the Tan ratio. Here is an 'aide memoire' for the Trig . functions. SOH , CAH, TOA. ( Said as 'soccatoa'). SOH = Sin(angle) = opposite/ hypotenuse = o/h CAH = Cos(angle) = adjacent/hypotenuse = a/h TOA = Tan(Angle) = opposite/adjacent = o/a
The side across from the right angle is called a leg?
It is the hypotenuse
How are side angle side triangles and Hypotenuse leg alike?
"Hypotenuse-leg" is not necessarily the right-triangle version of "side-angle-side". It's the right-triangle version of "side-side-side", because if you know that it's a right triangle, and you know the hypotenuse and a leg, then you can calculate the length of the other leg. If you want to work with "side-angle-side", and you know the hypotenuse and a leg, then you can find the angle between them, because it's the angle whose cosine is (the known leg) divided by (the hypotenuse), and you can look it up.
How do you find the base leg of a right triangle if you know the hypotenuse and one acute angle?
By using trigonometry that is applicable to a right angle triangle.
How do you solve a 30-60-90 degree?
To solve a 30-60-90 triangle, you need to know the length of one side. The hypotenuse is twice as long as the shortest leg (the side opposite the 30 angle) The longer leg (opposite the 60 angle) is the length of the shorter leg times the square root of 3. So in summary: If you know the hypotenuse, divide it by 2 to find the shorter leg, and multiply that times the square root of 3 to find the longer leg. If you know the longer leg, divide it by the square root of 3 to find the shorter leg, then multiply that by 2 to find the hypotenuse. If you know the shorter leg, multiply it by 2 to find the hypotenuse. Multiply the shorter leg length by the square root of 3 to find the longer leg.
What is a hypotenuse leg?
The hypotenuse leg of a right angle triangle is its longest side.
What are right triangle congruence theorem?
1.HyL Theorem (Hypotenuse-Leg) - if the hypotenuse and leg of one triangle is congruent to another triangle's hypotenuse and leg, then the triangles are congruent. 2.HyA (Hypotenuse-Angle) - if the hypotenuse and angle of one triangle is congruent to another triangle's hypotenuse and angle, then the triangles are congruent. 3.LL (Leg-Leg) if the 2 legs of one triangle is congruent to another triangle's 2 legs, then the triangles are congruent. 4.LA (Leg-Angle) if the angle and leg of one triangle is congruent to another triangle's angle and leg, then the triangles are congruent.
How do you use sine in math?
The sine function is used in trigonometric calculations when attempting to find missing side lengths of a right triangle. The sine of an angle in a triangle is equal to the length of the side opposite of that angle divided by the length of the hypotenuse of the triangle. Using this fact you can calculate the length of the hypotenuse if you know an angle measure and the length of one leg of the triangle. You can also calculate the length of a leg of the triangle if you know an angle measure and the length of the hypotenuse.
What are the four congruence theorem for right triangle?
four types aressssasrhsasa1.HyL Theorem (Hypotenuse-Leg) - if the hypotenuse and leg of one triangle is congruent to another triangle's hypotenuse and leg, then the triangles are congruent.2.HyA (Hypotenuse-Angle) - if the hypotenuse and angle of one triangle is congruent to another triangle's hypotenuse and angle, then the triangles are congruent.3.LL (Leg-Leg) if the 2 legs of one triangle is congruent to another triangle's 2 legs, then the triangles are congruent.4.LA (Leg-Angle) if the angle and leg of one triangle is congruent to another triangle's angle and leg, then the triangles are congruent.
What are the basic trigonometric ratios?
Sine(Sin) Cosine(Cos) Tangent(Tan) ---- -Sin of angle A=opposite leg of angle A / hypotenuse -Cos of angle A= Adjacent leg of angle A / Hypotenuse -Tan of angle A= opposite leg of angle A / Adjacent lef of angle A
How do you find another leg in Pythagorean theorem with the hypotenuse given?
The square of the hypotenuse minus the square of the leg you know will give you the square of the unknown leg.
I have a right angled triangle which i know all the angles of. I have the length of one side which is adjacent to the right angle. How can I work out the length of the hypotenuse and the other side?
Use tangent to find the other leg, and the sine or cosine to find the hypotenuse.
How do you find the hypotenuse with only a leg and a degree?
It depends on the position of the 'leg' compared to the known angle. If the 'leg' makes up one of the two sides of the angle, then the other side of the angle is the hypotenuse. In this case the 'leg' would be referred to as the 'adjacent' side. The side the doesn't form part of the angle is referred to as the 'opposite' side. So using the trig. functions. Sin(angle) = opposite / hypotenuse. Then algebraically rearranging hypotenuse = opposite / Sin(angle). Similarly for 'Cos'. Cos(angle) = adjacent/ hypotenuse Hence Hypotenuse = adjacent / Cos(angle) So as an example If the leg/opposite is 2 units. and the angle 30 degrees. Then hypotenuse = 2 / Sin(30). On you calculator you should be find the Sin( 30) = 1/2 = 0.5 Substitute in hypotenuse = 2 / 1/2 ( That is '2' divided by '1/2'), (Division of fractions). hypotenuse = 2 X 2/1 = 4/1 = 4 units. NB When using your calculator to find 'Sin' , 'Cos', and 'Tan' of angles, you will read out some 'horrible' decimal numbers. NNB Do NOT use the TAN(gent) function to find hypotenuse. It is NOT part of the Tan ratio. Here is an 'aide memoire' for the Trig . functions. SOH , CAH, TOA. ( Said as 'soccatoa'). SOH = Sin(angle) = opposite/ hypotenuse = o/h CAH = Cos(angle) = adjacent/hypotenuse = a/h TOA = Tan(Angle) = opposite/adjacent = o/a
The side across from the right angle is called a leg?
It is the hypotenuse
