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To find the sum of the interior angles of a regular polygon?
The sum of the interior angles of an n-sided polygon is 180n - 360 degrees.
If you know the sum of the angles of a regular polygon how can you find the measure of one of the congruent angles?
Each interior angle = sum of angles/number of sides
What is the formula to find the sum of interior angles of a polygon?
The formula to find the sum of interior angles of a polygon is 180° × (n - 2), where n is the number of sides of the polygon.
How do you find the interior angle of a polygon?
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. Once you have the sum, divide by the number of sides to find an individual angle.
What is the formula to find the sum of the interior angles of any polygon?
The sum of the interior angles (the angles of a polygon is equal to the 180*(n-2), where n is the number of sides. For example, if a polygon has 5 sides the sum of the angles is 180*(5-2), which is 540 degrees.
To find the sum of the interior angles of a regular polygon?
The sum of the interior angles of an n-sided polygon is 180n - 360 degrees.
What is the formula to find the interior angles of a polygon?
If the polygon is a regular polygon then all interior angels are equal to 180-(360/no of sides of the polygon)
How do you find the sum of angles in a n-sided polygon to give an expression for the measure of each interior angle of a regular n-gon?
It is: (number of sides -2)*180 = sum of interior angles If its a regular polygon then: sum of interior angles/number of sides = each interior angle
How to find interior angle of a regular polygon?
You use the fact that the sum of the interior angles of a regular polygon with n sides is:180(n-2) degreesNow you have the sum of measures of all the interior angles so divide that by n and you have the measure of each interior angle.
How do you divide a polygon into triangles to find the sum of its interior angles?
If a regular polygon has n sides, then the number of triangles in that polygon is n - 2. thus, the sum of its interior angles is equal to (n - 2)180°.
Find the measure of each of the interior angles of a regular ten sided polygon?
144 degrees
Describe how you could find the angle sum of a regular polygon that has N sides?
Interior angles of any polygon: (N-2)*180 = sum of interior angles when N is the number of sides
How do I get the degrees in the interior angles of a polygon?
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. To find an individual angle, divide that number by n.
One exterior angle of a regular polygon measures 40 What is the sum of the polygon's interior angle measures?
The sum of a regular polygon's interior angles is always equal to (n-2) * 180, where n is the number of sides in the polygon. Given that one exterior angle measures 40 degrees, we can find the interior angle by subtracting 40 from 180 degrees (since the exterior and interior angles are supplementary) to get 140 degrees. So, the sum of the interior angles of the regular polygon is 140 * n.
If you know the sum of the angles of a regular polygon how can you find the measure of one of the congruent angles?
Each interior angle = sum of angles/number of sides
What is the formula to find the sum of interior angles of a polygon?
The formula to find the sum of interior angles of a polygon is 180° × (n - 2), where n is the number of sides of the polygon.
What is the polygon that the sum of the measures of the interior angles is 3240 degrees?
To find the sum of interior angles for any N-sided polygon = N*180° - 360°Solve the equation: N*180° - 360° = 3240°, for N, and N = 20, so a 20 sided polygon will have sum of interior angles = 3240°, and if it is a regular polygon, then each angle = 162°
