Divide the perimeter by eight.
perimeter of octagon is 128 cm= 8 * side side of the octagon=128/8=16 cm
If a regular octagon has a perimeter of 40cm, then each side is 5 cm.
It is 72 cm/8 = 9 cm.
The perimeter of an octogon can be calculated by multiplying the length of one side by 8, so:Perimeter = side x 8 = 115 mm x 8 = 920 mm
-- Find the length of one side. -- Find the length of another side. -- Find the length of the remaining side. -- Add the three numbers. -- Their sum is the perimeter of the scalene triangle.
Perimeter = 8 x (length of one side)
The perimeter of an octagon that has one side of 2 inches is 16 inches.
perimeter of octagon is 128 cm= 8 * side side of the octagon=128/8=16 cm
The length of one side of an octagon, if the perimeter is 6 feet, is 9 inches.
If it's a regular octagon, the perimeter is 8 times the length of one side.
If a regular octagon has a perimeter of 40cm, then each side is 5 cm.
Octagon has 8 side. Total perimeter is 208 mm, hence each side = 208/8 = 26 mm
If the octagon is regular, then one side is 39 and there is 8 side, it will be 39*8The answer is 312 cm squaredIf it isn't a regular octagon, then there is no solution
The perimeter of an octagon is 64 only if it is a regular octagon and the length of one side is 8. An irregular octagon may or may not have a perimeter of 64 (whatever units of measure you choose to use) depending on what the lengths of the individual sides are.
Its perimeter is: 8*6 = 48 cm
It depends how big it is. But the rule is: Side length x 8 = Perimeter. For example, if one side was eleven centimeters long then the perimeter would be P= 11 x 8. It would be eighty-eight centimeters. Note: This rule only works for regular octagons. If you need to find the perimeter of an irregular octagon, then you have to measure each side and add up the measurements of each side.
208/8 = 26mm