If a regular octagon has a perimeter of 40cm, then each side is 5 cm.
9.84
40cm
The length of the other diagonal works out as 12cm
Perimeter = sum of the lengths of sides = 5* 7 cm = 35 cm
To find the area of a regular hexagon with side length of 40cm, consider that since it is regular, then it consists of 6 equilateral triangles of side 40cm. Half of each of those triangles is a right triangle. By the pythagorean theorem, we know that if the hypotenuse is 40cm, and one side is 20cm, then the other side is the square root of (40cm squared - 20cm squared) or about 34.64cm. That makes the area of each of those 12 right triangle to be about 692.8cm, so the total area of the hexagon is about 8313.8cm.
Perimeter = 40cm. Area = 100cm2
40cm
The perimeter is 40cm
Perimeter= 2length x 2widthSince the perimeter is 40 and 2 times the width is 16, that means 2 times the length is 24. The length is 12.
Perimeter = sum of the lengths of sides = 5* 7 cm = 35 cm
The length of the other diagonal works out as 12cm
The perimeter would be 40cm.
To find the area of a regular hexagon with side length of 40cm, consider that since it is regular, then it consists of 6 equilateral triangles of side 40cm. Half of each of those triangles is a right triangle. By the pythagorean theorem, we know that if the hypotenuse is 40cm, and one side is 20cm, then the other side is the square root of (40cm squared - 20cm squared) or about 34.64cm. That makes the area of each of those 12 right triangle to be about 692.8cm, so the total area of the hexagon is about 8313.8cm.
P = 160cm
First, you must find the width. Use Pythagoras' Theorem. Then, just add the lengths of the four sides, to get the perimeter.
Perimeter = 40cm. Area = 100cm2
40cm
35