At the point of intersecting lines, the points are equal.
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The equation of the 1st line is Y=3x-7
The equation of the 2nd line is Y=-2x+3
Remember, at the intersecting points they are equal. So then:
3x-7=-2x+3 Now solve for x (get x by itself in the form of x=whatever)
3x-7=-2x+3
+2x +2x (What you do to one side of the equal sign you must do to the other)
____________
5x -7 = 3
+7 = +7
____________
5x = 10 now divide by 5 to remove the 5 from the x in 5x.
___ ___
5 5
x=2
Then you sub x=2 into any of the two equation. Lets use the first one:
Y=3x-7 becomes Y=3(2)-7
Y=6-7
Y=-1
So the intersecting point is (2,-1)
You donβt. You just fail
The difference between interior lines and exterior lines are thatInterior lines: Are the lines that are in the inside of the shape or whatever you are trying to find the interior of.Exterior Lines: Are the lines that are outside of the shape or whatever you are trying to find the exterior of.
If the equations are in y= form, set the two equations equal to each other. Then solve for x. The x value that you get is the x coordinate of the intersection point. To find the y coordinate of the intersection point, plug the x you just got into either equation and simplify so that y= some number. There are other methods of solving a system of equations: matrices, substitution, elimination, and graphing, but the above method is my favorite!
The answer is 9.499 m approx.
In simple terms, if you draw lines from each corner/vertex, to the middle of the opposite side, you will find the lines converge or meet at one point. That point is the centroid.
to find the altitude of a triangle you connect each vertex perpendicularly to the opposite segment all three points will meet at one point known as the orthocenter -9th grader
Solve the two equations simultaneously. The solution will be the coordinates of the point of intersection.
It would help to know "... the point of intersection of a parallelogram" and what!
Graph the two lines or equations you want to find the intersection of. Then adjust the window so that you can see the intersection point. (If you don't know where it is, try pressing ZOOM and choosing ZoomFit.) Then press 2ND CALC (above TRACE) and choose option 5, intersect. Use the up and down arrows to select the first equation you want to find the intersection point on, and press ENTER. Do the same thing for the second equation. The calculator will now say "Guess?". Use the left and right arrows to move the x-like shape as close to the intersection point as possible, then press ENTER. The calculator will tell you the intersection point and the bottom of the screen. If you get a NO SIGN CHNG error, then it might be because the intersection point is not on the screen. Change the window so that you can see the intersection point and try again. Also, make sure that your guess is somewhat close to the intersection point.
another point
Unless the line is a subset of the plane, the intersection is a point.
There is a difference between where the two lines meet and where the greatest tempurature change is... think about it... the two lines do not meet where the greatest tempurature change is, the two lines meet where the greatest amount of heat is given off...
graphing method is when you graph two lines and then find the intersection which is the answer of the system of equations
when the x and y values of both equations are equal, because the point of intersection will only have one x value and one y value
You must first write an equation for the line through the point perpendicular to the line. Then, find the intersection between the two lines. Lastly, use this point and the distance formula to find the length of the perpendicular segment connecting the given point and the original line. That will lead to the following formula, d = |AX1+BY1- C|/(sqrt(A2+B2)), Where A, B and C represent the coefficients of the given line in standard form and (X1,Y1) is the given point.
Yes, an Octagon does have a center point. The easiest way for me to find this is by drawing lines between opposite vertexes. You should end up with four lines and they should be crossing at one point. That is your center point! :V
The step to verify an isosceles triangle is: 1) Find the intersection points of the lines. 2) Find the distance for each intersection points. 3) If 2 of the distance are the same then it is an isosceles triangle.
Assume the room to be square or rectangle. The intersection of two lines from opposite corners is your center.