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The ratio of the perimeters is equal to the scale factor. If rectangle #1 has sides L and W, then the perimeter is 2*L1 + 2*W1 = 2*(L1 + W1).

If rectangle # 2 is similar to #1 and sides are scaled by a factor S, so that L2 = S*L1 and W2 = S*W1, the perimeter of rectangle #2 is 2*(L2 + W2)= 2*(S*L1 + S*W1) = S*2*(L1 + W1) = S*(perimeter of rectangle #1).

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Q: How do you find the ratio of the perimeter of two similar rectangles?

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It is k times the perimeter of eh where k is the constant ratio of the sides of abcd to the corresponding sides of efgh.

4 x 4 and 6 x 3

7:3

I don't understand why there are so many questions about rectangles' perimeter. You just add the length and the width and double your answer....

56 (: When we say polygon abcd is similar to polygon afge, they already told you which are the lines that are similar. ab:af=bc:fg=cd:ge etc. Lines ad and af are not similar in length and therefore cannot be used to find perimeter of polygon abcd even though the perimeter of polygon afge is given.

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You need to find the perimeter of one by adding together the lengths of all its sides. The perimeter of the similar shape is the answer multiplied by the similarity ratio.

2l+2w

Here's how to do that: 1). Find its length. 2). Find its perimeter. 3). Divide (its length) by (its perimeter). The quotient is the ratio of its length to its perimeter.

perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement

10cm by 10cm (perimeter=40cm), 5cm by 20cm (perimeter=50cm), 50cm by 2cm (perimeter=104cm), 100cm by 1cm (perimeter=202cm). All of these rectangles' areas are 100cm2

If you are trying to find the ratio of the lengths of two similar rectangles, divide the length of one side of one rectangle by the corresponding side length of the other rectangle. To find the ratio between their volumes, divide the volume of one rectangle by the volume the other rectangle. To find volume, multiply the width of the rectangle by the length of the rectangle.

There is no relationship between the perimeter and area of a rectangle. Knowing the perimeter, it's not possible to find the area. If you pick a number for the perimeter, there are an infinite number of rectangles with different areas that all have that perimeter. Knowing the area, it's not possible to find the perimeter. If you pick a number for the area, there are an infinite number of rectangles with different perimeters that all have that area.

If you are given two similar rectangles, one with all measurements and the other with only one, you first need to find the conversion ratio. Let's call the rectangle that you know everything about, rectangle A, and the other rectangle B. You take the ratio of the side of rectangle B to rectangle A. You then multiply the length of rectangle A by this value, to find the length of rectangle B.

The perimeter of the larger polygon will have the same ratio to the perimeter of the smaller as the ratio of the corresponding sides. Therefore, the larger polygon will have a perimeter of 30(15/12) = 37.5, or 38 to the justified number of significant digits stated.

It is k times the perimeter of eh where k is the constant ratio of the sides of abcd to the corresponding sides of efgh.

8:32

You cannot.You cannot.You cannot.You cannot.

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