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3s=2t can also be written as 3y=2x or 3x=2y. Either way, it is linear.
To find out if it is linear, simply graph it. If you can draw a completely vertical line through any point of the graph without intersecting more than one point of the graph, then it is linear.
This equation (3s=2t), it is linear.
What else can I help you with?
What is the integral of 2 times 1-x dx with limits 0 to t?
,/` 2(1 - x) dx,/` 2 - 2x dx2x - x2 ...evaluated from 0 to t gives us...2t - t2 - [2(0) - (0)2]2t - t2
What is the Laplace transform of 1-cos(2t)t?
To find the Laplace transform of the function ( f(t) = 1 - \cos(2t)t ), we can use the linearity of the Laplace transform. The transform of ( 1 ) is ( \frac{1}{s} ). For the term ( -\cos(2t)t ), we use the property ( \mathcal{L}{t f(t)} = -\frac{d}{ds} \mathcal{L}{f(t)} ). Thus, the overall Laplace transform is: [ \mathcal{L}{1 - \cos(2t)t} = \frac{1}{s} - \frac{d}{ds} \left( \frac{s}{s^2 + 4} \right) = \frac{1}{s} - \frac{4}{(s^2 + 4)^2}. ]
What is the limit as t approaches 0 of 2t tan t?
That would be 0. (But that was too easy. Did you mean something else?)
How do you make a the subject of t equals 0.5 x a plus b x h?
To make the following relationship: t = (1/2)a +bh a function of "a" (a = ...) start by subtracting both sides by "bh": t - bh = (1/2)a then divide both sides by (1/2), which is the same as multiplying by 2: 2(t - bh) = a from here you can distribute the 2 if desired: a = 2t - 2bh
Integration of tangent cubed of x?
Find I = ∫ tan³ x dx. The solution is: I = ½ tan² x - log cos x. * * * Here is how we can obtain this result: First, let t = tan x, s = sin x, and c = cos x; then, dI = t³ dx, ds = c dx, dc = -s dx, and dt = (1 + t²) dx; and, of course, t = s / c. By algebra, t³ = t(t² + 1) - t; thus, we have dI = t³ dx = t(t² + 1) dx - t dx = t dt - t dx. Now, d (t²) = 2t dt; thus, t dt = ½ d(t²). On the other hand, we have d log c = dc / c = -s dx / c = -t dx; thus, t dx = -d log c. Combining these results, we have dI = t dt - t dx = ½ d(t²) - d log c. This integrates readily, giving I = ½ t² - log c, which is the solution we sought. * * * We may check our result, by differentiating back: dt / dx = 1 + t²; and d(t²) / dt = 2t; thus, (d/dx)(t²) = 2t dt / dx = 2t (1 + t²). Also, we have d log c / dc = 1 / c; and dc / dx = -s; whence, (d/dx)(log c) = (dc / dx) / c = -s / c = -t. Then, dI / dx = ½ (d/dx)(t²) - (d/dx)(log c) = t (1 + t²) - t = t + t³ - t = t³, re-assuring us that we have integrated correctly.
Is the equation 3s equals 2t linear or nonlinear?
A linear equation has no higher powers than 1. This is linear.
What is 2t equals 10?
An equation?
How do you solve 5-b equals 2t algebra?
It is not possible to solve a single linear equation in two unknown variables (b and t).
Solve the following equation 19-2t equals 7?
19-2t = 7 -2t = 7-19 -2t = -12 t = 6
Which equation is equivalent to 4t equals 20?
-2t = -10
Solve for t in the equation 3t plus 7 equals 2t-5?
3t + 7 = 2t - 5 3t = 2t - 12 t = -12
What will be the formula if c is unknown using kVp equals 2t plus c?
Rearranging the the equation to make c the subject:- c = kVp-2t
How do you solve the equation 3 tan 2t equals sq rt 3?
3tan (2t) = sqrt(3) tan (2t) = sqrt(3)/3 = 0.577 from tangent tables, 2t = 30 degrees t = 15 degrees
Is t plus t equals 2t or t squared?
2t
2t - 3 - 3 equals 7?
2t-3-3 = 7 2t = 7+6 2t = 13 t = 6.5
What is 2t plus 8 equals 3t-11?
In 2t+8 19
What is 75 plus 2t equals 100-2t?
Heyy, For this question, we first need to add 2t to both sides of the equation to get: 75 + 4t = 100 Now, subtract 75 from both sides of the equation to get: 4t = 25 At this time, divide both sides by 4 to get t alone and get: t = 25 / 4 OR 6.25 FINAL ANSWER = t=6.25
