I'm fairly certain that this cannot be done.
Oh, dude, you just gotta draw two diagonal lines from one corner to the opposite corner, creating four triangles, and then draw a line horizontally across the middle of the rectangle. Boom, five equal parts! It's like slicing a pizza, but with shapes.
Its diagonals divides it into two equal right angle triangles.
prove any two adjacent triangles as congruent
Select any one side and divide its length into 5 equal parts. Draw lines that are parallel to the adjacent side to the opposite side. This will divide the rectangle into 5 equal strips.
No, it is not possible to divide a trapezium into two congruent triangles. A trapezium has only one pair of parallel sides, while a triangle has no parallel sides. Therefore, it is not geometrically feasible to divide a trapezium into two congruent triangles.
Oh, dude, you just gotta draw two diagonal lines from one corner to the opposite corner, creating four triangles, and then draw a line horizontally across the middle of the rectangle. Boom, five equal parts! It's like slicing a pizza, but with shapes.
Its diagonals divides it into two equal right angle triangles.
Yes, two equal right-angle triangles.
Well, honey, to divide a rectangle into 7 equal parts, you can start by drawing three equally spaced horizontal lines and three equally spaced vertical lines inside the rectangle. This will give you 9 smaller rectangles. Then, you can simply combine two of these smaller rectangles to create 7 equal parts. Voila! Just like that, you've divided that rectangle into 7 equal parts.
Impossible
Might be divide it to rectangle
You divide it into parts of 1.2by4
Select any one side and divide its length into 5 equal parts. Draw lines that are parallel to the adjacent side to the opposite side. This will divide the rectangle into 5 equal strips.
prove any two adjacent triangles as congruent
Yes if it's divided diagonally.
have have to divide them
Yes, they do.