Well, that isn't a proper equation but if the equation is, y=4x(+/-)9... First: Put the "b" value into your graph. The "b" value is on the y-intercept, in this case, it would be (+/-)9. If it is +9, put it 9 values up on the y-axis. Vice-versa if negative. Second: The 4x would be the slope. The 4 represents the "a or m" value. Since the slope is 4, then you would start at the (+/-)9 and go UP:4 and OVER:1. This is the Rise Over Run technique. The reason you go over 1 is because 4=4/1 the 4 represents rise and the 1 represents run. (If the "m"value was 1/4 then you'd go up 1 and over 4). Lastly: Repeat that method over and over again until you run out of room on your graph. Then make a line connecting each dot and at the end of each line put arrows pointing outward displaying that the slope will be infinite.
If you mean y = 4x-6 then the slope is 4 and the y intercept is -6
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y = 4x + 2 It has a slope (gradient) or 4. The slope/gradient of a linear function is simply the number in front of the x when the equation is in the form y=mx+b. (the coefficient of x).
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The function y = x is the graph that passes from the points (-1, -1), (0, 0), and (1, 1) The function y = 4x is the graph that passes form the points (-1, -4), (0, 0), and (1, 4) Sketch these graphs in a same x and y coordinate system, and you can see both of them
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To find the equation of a line perpendicular to ( y = 4x + 3 ), we first determine the slope of the given line, which is 4. The slope of a line perpendicular to it is the negative reciprocal, so it would be ( -\frac{1}{4} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with the point (-8, 5) and the slope ( -\frac{1}{4} ), the equation becomes ( y - 5 = -\frac{1}{4}(x + 8) ). Simplifying this gives the equation of the perpendicular line.
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Without an equality sign the expression given can't be considered to be an equation.