Switch the coordinates and change the sign of the second one by multiplying it by negative 1.
Here are some examples and a more general way to understand the problem.
Consider the point (1,1), a 90 degree rotation clockwise about the origin would move it into the 4th quadrant.
The new point is (1,-1) , similarly (-4,2)-> (2,4), (-4,3)-> (3,4)
We take a point p= (x,y) the the result of rotation p 90 clockwise about the orgin is a new point p'=(x',y')= (-y, x). .
In the case of p=(1,0) the new point is p'= (0, -1)
One can use a matrix where the first row is cos(a), sin(a) and the second row is
-sin(a) cos(a) for any clockwise rotation of a degrees about the origin.
If we let a=90 degrees we have
[0 1] as the first row and [-1 0] as the second row. So the matrix is:
|0 1|
|-1 0|
Call that matrix M
So a point p= (x,y) can be multiplied by M as follows Mp=p' where p' is the rotated point.
If p=(-4,2) then Mp
is M(-4,2) which after matrix multiplication means x'=0*-4+1*2=2 and y'=-1*-4+0*2=4
So p'=(2,4)
Try it with (1,0)
x'=1*0+0*1=0
y'=-1*1+0*1=-1
so p'=(0,-1) and (1,0)->(0,-1)
How about the point on the y axis (0,1), it should go to the point (1,0)
0*1+1*1=1 and -1*0+0*1 gives you the pont (1,0) ( we don't see the negative sign because -0 is just 0)
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You dont, its just 90 degrees 3 times..
Move it 3 times* * * * *or once in the anti-clockwise direction.
To rotate a figure 180 degrees clockwise about the origin you need to take all of the coordinates of the figure and change the sign of the x-coordinates to the opposite sign(positive to negative or negative to positive). You then do the same with the y-coordinates and plot the resulting coordinates to get your rotated figure.
rotate it 90 degrees
I dont really know if this is right but i think to do this problem you have to take a point then rotate the paper counter clockwise around the origin then you have a new point which is called a prime. Then reflect it over the y axis on the graph.