0
What else can I help you with?
The length of a rectangle is twice its width If the perimeter of the rectangle is 54y find its area?
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
How do you find the length of a rectangle when the width and area are provided?
For a rectangle, area equals length times width. To find the length given the width and area, divide the area by the width.
The length of a rectangle is twice its width If the perimeter of the rectangle is 60cm find its area?
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
The length of a rectangle is twice its width the perimeter of the rectangle is 42ft find the area?
98 square feet
How do you find the length of a rectangle if you have the width and the area?
divide area by width and voila! u get the length
The length of a rectangle is twice its width If the perimeter of the rectangle is 54y find its area?
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
How do you find the length if you already have the width and the area?
If Length * Width = Area, then Area ÷ width = Length
How do you find the length if the width and area is given?
Area = (length) times (width)Length = (area) divided by (width)Width = (area) divided by (length)
How do you find the length of a rectangle when the width and area are provided?
For a rectangle, area equals length times width. To find the length given the width and area, divide the area by the width.
How do you find a relationship in width and area?
To find the relationship in width and area you can use the formula area/length = width. To find the area of a room you multiple the length by the width.
The length of a rectangle is twice its width If the perimeter of the rectangle is 60cm find its area?
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
The length of a rectangle is twice its width the perimeter of the rectangle is 42ft find the area?
98 square feet
The area of a rectangular patio is 900ft2 The patio's length is twice its width Find the dimensions of the patio?
AREA = LENGTH x WIDTH LENGTH = 2 X WIDTH AREA = 2 x WIDTH X WIDTH = 900 900/2 = WIDTH X WIDTH 450 = WIDTH X WIDTH = WIDTH SQUARED WIDTH = SQUARE ROOT (450) = 21.21 FEET LENGTH = 42.42 FEET
How do you find the width of a rectangle with area and length?
Width * Length = Area so..... Width = Area / Length
How do you work out find out the area when the length is twice the with?
You just multipy the length (no matter what it is) by the width (no matter what that is). So... L x W = A Where L is Length, W is Width and A is Area. For your question about the area of a rectangle where the length is twice the width but no numbers are given then I guess a formula could be W x 2W = A. Or send me the exact question and I'll see if I can think of a better answer.
How do you find area when length is given?
Find the width, and multiply the length and the width.
How do you find the length of rectangle or square if the area and width are known?
For a rectangle or square, Area = Length * Width So Length = Area / Width.
