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Suppose the smaller side is x cm

Then the greater side is x+1.5 cm

The area is 0.5*(sum of parallel sides)*height

So 0.5*(x+x+1.5)*16 = 212

ie 8*(2x+1.5) = 212

2x + 1.5 = 212/8 = 26.5

2x = 25

x = 12.5

and then the other side is x+1.5 = 14

The sides are 12.5cm and 14cm

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Q: How do you work out the lengths of the parallels of a trapezoid when one base is 1.5 cm greater than the other and has a height of 16 cm with an area of 212 square cm?
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