Easy . Think of it like this. The higher you angle your catapult (or whatever your using.) The higher it will travel but it will have less power. If you have a lower angle you will have more power but it your projectile will hit the ground first. If you don't understand just play around with a slingshot and an empty can of soda. Or you could test it out this theory by playing around with angry birds ;)
in a frictionless vacuum, 45°, otherwise (on earth), aim to have the projectile release when the arm is at about 40° from the base
The range of projectile is maximum when the angle of projection is 45 Degrees.
The difference of these two is that pullback is how far and launch angle is the elevation. I'm not sure but you can check on Science Buddies or just google it .
The [horizontal] range of a projectile is maximised when it shoots at a 45 degree angle. This is true if air resistance is ignored so that the only force acting on the projectile is gravity.
45 degrees to the horizontal will give the maximum flight time for a projectile. If a projectile was fired at 90 degrees to the horizontal, (straight upwards) the projectile will go straight upwards (ignoring the shape, form and aerodynamic properties of the projectile). Likewise if you were to fire a projectile at 0 degrees to the horizontal, the projectile would follow said course, IF gravity was not in effect; a projectile needs some form of vertical velocity to overcome gravity. Hence why 45 degrees will give you the longest distance and consequently flight time.
This means 'High Trajectory'. That is, a high launch angle.
A trajectory is the angle made with the horizontal when a projectile is fired. Suppose the projectile is a cannon ball. Assuming air is frictionless, that cannon ball will travel the greatest distance if the trajectory is 45 degrees from horizontal.
It depends on the angle and speed at which it is fired.
if a body is thrown having initial velocity and make angle with ground this body is known as projectile and the way is calle trajectory
The vertical component of the projectile's motion is uniformly accelerated, no matter what the angle of launch was.
The half maximum range of a projectile is launched at an angle of 15 degree
yes it does. you see if you have it set up at a a 90 degree angle it will go further than it would of a 10 degree angle A projectile leaving the ground at an angle of 45 degrees will attain the maximum range. Fire it straight up and it will fall back to its launch location (wind effects etc. ignored). Fire it horizontally and it will hit the ground very much the same time as if it was dropped from its launch platform at the same time. That would not be very far.
If space were entirely empty this would be true, but even minute gravitational forces can change the trajectory and velocity of a projectile.
look up naked penus Wow. Some people have nothing to do but waste time. There is no way to answer that as asked A very general answer is, whatever angle will cause the projectile to land where you want it to.
Some of the factors that determine the movements of a projectile include: air resistance, force of gravity, initial launch velocity, the angle a projectile was launched at, and the objects initial elevation.
Its an equation used to find the 2D motion of a projectile; y=xtan*0-gx2/2u2cos2* where * represents an angle b/w them
Not sure