If AB is a perpendicular bisector of CD then four 90 degreee angles are formed.
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None. A perpendicular line is two lines joined together to make a right angle(90degrees). A hexagon has no right angles so there are no perpendicular lines. None, by definition perpendicular means a 90 degree intersection of two lines. A hexagon's intersections are only 60 degrees.
None but its diagonals are perpendicular lines intersecting each other at right angles.
0 perpendicular lines. There are no 90 degree angles within a hexagon. Perpendicular lines meet at a right angle and sometimes they intersect.
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Being 'perpendicular' would require the lines to be at 'right angles' to each other... So, if working in a 2-dimensional setting, the joining of 3 perpendicular lines would not be possible. If working in a 3-dimensional setting, the answer would be 12. Four from the intersection of the 1st and 2nd lines, four from where the 3rd line intersects initially, and four from where the 3rd line leaves the intersection.
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When two perpendicular lines cross you get four equal angles of 90 degrees.
Depending on the location of the intersection, there are many things though could be formed, but to pick commons, it could form a +, T, L
A circle does not have angles in the traditional sense, as angles are formed by the intersection of two lines. However, if considering angles formed by radii and chords within the circle, it is possible to have infinitely many obtuse angles depending on the selected points on the circumference. Thus, the answer can be considered as infinite obtuse angles in a circle.
Two intersecting lines form four angles. Each pair of opposite angles created by the intersection is equal, resulting in two pairs of vertical angles. These angles sum up to 360 degrees around the point of intersection.
A pentagonal prism has 10 right angles, formed from perpendicular edges. It has one for each angle made when a face meets a base. Since it has 5 faces and 2 bases, there are 10 right angles.
If the lines are perpendicular, which is to say, intersect at right angles, then all four angles are congruent, since they will all be 90o. If the intersection is not perpendicular, then there are two sets of congruent angles. Opposite angles will be equal. That is to say, if you imagine the angles forming at more or less the cardinal points of the compass, the north and south angles will be equal, and the east and west angles will be equal.
16 angles, 8 of each measure - unless the transversal is perpendicular in which case, all 16 angles are right angles.