A square has only to diagonals and either one will divide it in half.
Since the diagonals of a rhombus are perpendicular between them, then in one forth part of the rhombus they form a right triangle where hypotenuse is the side of the rhombus, the base and the height are one half part of its diagonals. Let's take a look at this right triangle.The base and the height lengths could be congruent if and only if the angles opposite to them have a measure of 45⁰, which is impossible to a rhombus because these angles have different measures as they are one half of the two adjacent angles of the rhombus (the diagonals of a rhombus bisect the vertex angles from where they are drawn), which also have different measures (their sum is 180⁰ ).Therefore, the diagonals of a rhombus are not congruent as their one half are not (the diagonals of a rhombus bisect each other).
To divide a square in half four different ways, you can draw two diagonals intersecting at the center, creating four equal triangles. Another way is to draw a horizontal line passing through the center of the square, dividing it into two equal rectangles. You can also draw a vertical line through the center to create two more equal rectangles. Lastly, you can divide the square into four smaller squares by drawing two perpendicular lines through the center.
You can divide the square from a point halfway between two of the corners to a similar point on the opposite side, to produce to rectangles. You can do this vertically or horizontally, but the result is the same. The second method is to divide the square from one corner to the corner directly opposite to it, in effect dividing the square into two triangles.
An acre is 43,560 square feet. Half an acre is half that amount. Choose any number of feet for the length, then divide the square feet (for half an acre) by that number to get the width.
A set square is known as a set square and not triangle because when you divide 180 by 4, then you get 45. Now, if you construct a square with side: 45 degrees and then divide it in half, then you get the measurement 45-45-90.
Just one diagonal will divide a hexagon into two halves
To find the length of each diagonal of a square, divide the sum of the diagonal lengths by 2. Since a square has two diagonals of equal length, this division will give you the length of each diagonal.
Probably 6 if not 4 if not 8 if not 10.WHO CARES
If this is a rhombus then the area is half the product of the diagonals - 10 x 14 = 140. Half of 140 = 70, so the area is 70 square feet.
Evenly draw a line to split the shape in half. In this case, we have a square, so we can cut in many places such as the two diagonals, vertically, and horizontally.
Since the diagonals of a rhombus are perpendicular between them, then in one forth part of the rhombus they form a right triangle where hypotenuse is the side of the rhombus, the base and the height are one half part of its diagonals. Let's take a look at this right triangle.The base and the height lengths could be congruent if and only if the angles opposite to them have a measure of 45⁰, which is impossible to a rhombus because these angles have different measures as they are one half of the two adjacent angles of the rhombus (the diagonals of a rhombus bisect the vertex angles from where they are drawn), which also have different measures (their sum is 180⁰ ).Therefore, the diagonals of a rhombus are not congruent as their one half are not (the diagonals of a rhombus bisect each other).
47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.
To divide a square in half four different ways, you can draw two diagonals intersecting at the center, creating four equal triangles. Another way is to draw a horizontal line passing through the center of the square, dividing it into two equal rectangles. You can also draw a vertical line through the center to create two more equal rectangles. Lastly, you can divide the square into four smaller squares by drawing two perpendicular lines through the center.
Oh, dude, it's like the diagonals in a rhombus are totally those lines that connect the opposite corners. They're like the fancy crossroads of the rhombus world, making all those right angles and stuff. So yeah, if you ever need to find them, just look for those lines that cut the rhombus in half diagonally.
You can divide the square from a point halfway between two of the corners to a similar point on the opposite side, to produce to rectangles. You can do this vertically or horizontally, but the result is the same. The second method is to divide the square from one corner to the corner directly opposite to it, in effect dividing the square into two triangles.
Each diagonal runs from one corner of the shape to an opposite corner, so each diagonal requires 2 corners. So in a hundred cornered shape there will be half of a hundred diagonals, which is 50. Just divide the number of corners by 2. So for a hexagon, which has 6 sides and 6 corners, there are 3 diagonals.
Answer: 144 and a half (divide by 9.)But that assumes that there is no waste.