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47 sides.
Take a vertex of an n-sided polygon.
There are n-1 other vertices.
It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it.
Thus n-3 diagonals can be drawn in from each vertex.
For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex.
The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely:
number of diagonals in an n-sided polygon = n(n-3)/2.
What else can I help you with?
How many diagonals can you draw from one vertex in a polygon with 35 sides?
In a polygon with ( n ) sides, the number of diagonals that can be drawn from one vertex is given by the formula ( n - 3 ). For a polygon with 35 sides, this means you can draw ( 35 - 3 = 32 ) diagonals from one vertex. Thus, from one vertex in a 35-sided polygon, you can draw 32 diagonals.
How many diagonal can be drawn from a regular hexagon from one vertex?
5 diagonals * * * * * That is not correct since two of these would be lines joining the vertex to adjacent vertices (one on either side). These are sides of the polygon, not diagonals. The number of diagonals from any vertex of a polygon with n sides is n-3.
What can you say about the relationship of the number of diagonals that can be drawn from each vertex of a polygon?
The formula for the number of diagonals is: 0.5*(n^2-3n) whereas 'n' is the number of sides of the polygon
What rule can be used to find number of diagonals that can be drawn from one vertex of regular polygon?
You can use the formula D=S-2 where D is the number of possible diagonals and S is the number of sides the polygon has.
How many diagonals can be drawn from one vertex of a 12 sided polygon?
10 ... any polygon it is 2 less than the number of sides or vertices wince they are the same.
How many diagonals can you drawn from one vertex in a 35 sided polygon?
In a polygon with n sides, the number of diagonals that can be drawn from one vertex is given by the formula (n-3). Therefore, in a 35-sided polygon, you can draw (35-3) = 32 diagonals from one vertex.
How many diagonals can you draw from one vertex in a polygon with 35 sides?
In a polygon with ( n ) sides, the number of diagonals that can be drawn from one vertex is given by the formula ( n - 3 ). For a polygon with 35 sides, this means you can draw ( 35 - 3 = 32 ) diagonals from one vertex. Thus, from one vertex in a 35-sided polygon, you can draw 32 diagonals.
What statement can you make about the number of diagonals that can be drawn from one vertex in a polygon?
Number of sides minus two equals number of diagonals drawn from one vertex.
If in a 54 sided polygon all possible diagonals are drawn from one vertex they divide the interior of the polygon into how many regions?
In a 54-sided polygon, 53 possible diagonals can be drawn from one vertex to another. These diagonals will not intersect. Therefore, the interior will be divided into 54 regions by the 53 diagonals plus the two sides of the original polygon that adjoin the vertex from which the diagonals are drawn.
How many diagonal can be drawn from a regular hexagon from one vertex?
5 diagonals * * * * * That is not correct since two of these would be lines joining the vertex to adjacent vertices (one on either side). These are sides of the polygon, not diagonals. The number of diagonals from any vertex of a polygon with n sides is n-3.
What can you say about the relationship of the number of diagonals that can be drawn from each vertex of a polygon?
The formula for the number of diagonals is: 0.5*(n^2-3n) whereas 'n' is the number of sides of the polygon
The number of diagonals that can be drawn in a polygon with n sides can be determined by nn - 32 How many diagonals can be drawn in a polygon with 10 sides?
38 diagonals
What rule can be used to find number of diagonals that can be drawn from one vertex of regular polygon?
You can use the formula D=S-2 where D is the number of possible diagonals and S is the number of sides the polygon has.
How many diagonals can be drawn from one vertex of a 12 sided polygon?
10 ... any polygon it is 2 less than the number of sides or vertices wince they are the same.
How many diagonals can be drawn from a vertex of an n gon?
n-3 diagonals. Of the n vertices of the polygon, you cannot draw diagonals to the two adjacent vertices since these are sides of the polygon and so not diagonals. And you cannot draw a diagonal from a vertex to itself. So those are three vertices that are ruled out, leaving n-3.
How many triangles can be formed by a diagonal drawn from a fixed vertex of a polygon with 17 sides?
In a polygon with 17 sides, a diagonal can be drawn from a fixed vertex to any of the other non-adjacent vertices. From one vertex, there are 14 other vertices (17 total vertices - 1 fixed vertex - 2 adjacent vertices) to which diagonals can be drawn. Each diagonal creates a triangle with the fixed vertex and two of the vertices connected by the diagonal. Therefore, the number of triangles that can be formed is equal to the number of diagonals, which is 14.
How many diagonals can be drawn from one vertex of a decagon?
Oh, dude, a decagon has 10 sides, right? So, if you pick one vertex and want to draw diagonals, you can draw diagonals to all the other vertices except the adjacent ones, which are already sides. So, you can draw 7 diagonals from that one vertex. Math can be fun, like a puzzle... or a headache, depending on how you look at it.
