Calculate the volume (cubic ft capacity) of the pool and multiply by the number of gallons per cubic foot. To calculate, the formula is V = (Pi x R²)(H) where Pi = 3.1416, R² is the radius multiplied by itself (radius is one-half of the diameter), and H is the height or depth. There are 7.481 gallons of water in 1 cubic foot. V = (3.1416 x 12²)(4) = (3.1416 x 144)(4) = (242.3904)(4) = 1809.5616 cu ft 1809.5616 x 7.481 = 13,537.33 gallons
If the pond is uniformly 6-feet deep it would contain about 1,955,109 gallons of water.
A 25-acre pond that is uniformly 6 feet deep will hold about 48,877,714 gallons of water.
That all depends on how deep the 530 sq ft area is
Here is my take: 1 gallon of water equals 231 cubic inches 1 square foot, 1 inch tall equals 144 cubic inches (12"x12"X1") 1 square foot needs 0.624 gallons to equal 1 inch of cover (144 cubic inched divided by 231 cubic inches) 16 square feet would require 9.975 gallons of water to be covered 1 inch deep. (16*0.624) **Runsky**
The answer depends on the type of liquid and dimensional units. Presuming water and feet, you can compute the volume as 30x24015=10800 cu ft The conversion is 7.48 gallons per cu ft which gives 80784 gallons. cu ft denotes cubic feet. If dimensions are in inches, incorporate the conversion of inches to feet.
3,398.4 gallons.
5,974 gallons.
1,770 gallons.
6,200 gallons.
Three feet of water in a 12-foot round pool is about 2,550 gallons.
About 5,310 gallons.
About 13,010 gallons.
2,360 gallons.
About 19,355 gallons.
9,440 gallons.
26,550 gallons.
About 212 gallons.