To calculate the volume of water in a round pool, you can use the formula for the volume of a cylinder: V = πr^2h, where r is the radius and h is the height. In this case, the radius is half the diameter, so it is 12 feet. Plugging in the values, we get V = π(12^2)(4) = 576π cubic feet. To convert cubic feet to gallons, you would multiply by 7.48, the number of gallons in a cubic foot, so the pool would hold approximately 4309 gallons of water.
If the pond is uniformly 6-feet deep it would contain about 1,955,109 gallons of water.
A 25-acre pond that is uniformly 6 feet deep will hold about 48,877,714 gallons of water.
That all depends on how deep the 530 sq ft area is
Here is my take: 1 gallon of water equals 231 cubic inches 1 square foot, 1 inch tall equals 144 cubic inches (12"x12"X1") 1 square foot needs 0.624 gallons to equal 1 inch of cover (144 cubic inched divided by 231 cubic inches) 16 square feet would require 9.975 gallons of water to be covered 1 inch deep. (16*0.624) **Runsky**
There are 43,560 square feet in one acre. Water is often measured in gallons, and one cubic foot of water contains approximately 7.48 gallons. Therefore, one acre of water, to a depth of one foot, would contain about 325,851 gallons (43,560 square feet x 7.48 gallons per cubic foot).
1,770 gallons.
3,398.4 gallons.
6,200 gallons.
5,974 gallons.
Three feet of water in a 12-foot round pool is about 2,550 gallons.
About 5,310 gallons.
2,360 gallons.
About 19,355 gallons.
26,550 gallons.
9,440 gallons.
About 212 gallons.
About 13,010 gallons.