A 25-acre pond that is uniformly 6 feet deep will hold about 48,877,714 gallons of water.
43560 sq ft = 1 acre 210 ft x 200 ft = 42000 sq ft = 42000 ÷ 43560 acre = 350/363 acre ≈ 0.964 acre
Answer: 1 acre = 43,560 square feet.
One foot deep, covering an acre. It equates to 325,900 gallons.
A sixty-acre lake averaging 20 feet deep has a volume of 391,021,200 gallons.
A 1000 acre lake that is 7 feet deep (uniformly) will have 7000 acre feet of water in it. An acre foot is an acre of water one foot deep, and the unit is used to measure reservoir water capacity. The conversion factor is that one acre foot equals about 325,851.5 gallons. The lake in question is holding 7000 times 325,851.5 gallons of water.
Approximately 488,777 gallons of water.
Approximately 8,146,286 gallons of water.
1 acre = 43560 sq.feet. 1 foot deep water over an acre is 43560 cubic feet, which is 325851.4 gallons in 1 foot deep. If it is 1 inch deep (1/12 foot) then it is 27154.3 gallons in 1 inch deep.
Approximately 977,553 gallons of water.
This pond would have a volume of about 3,258,510 gallons of water.
Six acre-feet of water is about 1,955,109 US gallons.
80,000 US gallons of water is about 0.25 acre feet.
Approximately 325,851 gallons.