A 25-acre pond that is uniformly 6 feet deep will hold about 48,877,714 gallons of water.
158
4.0 acre-feet
(250,000,000 gallons) x (231 in3/gal) x (1 foot/12inch)3 x (1 acre/43,560 ft2) =767.221 acre-feet. (rounded) What does this mean ? Right now, it looks kind of ridiculous.Well, it's not so bad. It means a foot of rain over 767 acres, or about1.44 inches of rain over 10 square miles, which isn't so unreasonable.
43560 sq ft = 1 acre 210 ft x 200 ft = 42000 sq ft = 42000 ÷ 43560 acre = 350/363 acre ≈ 0.964 acre
A 1000 acre lake that is 7 feet deep (uniformly) will have 7000 acre feet of water in it. An acre foot is an acre of water one foot deep, and the unit is used to measure reservoir water capacity. The conversion factor is that one acre foot equals about 325,851.5 gallons. The lake in question is holding 7000 times 325,851.5 gallons of water.
1 acre = 43560 sq.feet. 1 foot deep water over an acre is 43560 cubic feet, which is 325851.4 gallons in 1 foot deep. If it is 1 inch deep (1/12 foot) then it is 27154.3 gallons in 1 inch deep.
Approximately 977,553 gallons of water.
Approximately 8,146,286 gallons of water.
Six acre-feet of water is about 1,955,109 US gallons.
1,135 acre-feet of water equates to 369,841,371 US gallons.
A 25-acre pond that is uniformly 6 feet deep will hold about 48,877,714 gallons of water.
I'm assuming you mean acre feet of water. If that is the case, then there are 325,850.58 gallons in one acre foot of water or 4,887,758.7 gallons of water in 15 acre feet of water.
22 acre-feet equates to 7,169,000 gallons of water.
8 billion gallons is 24,551 acre-feet.
43560x7x7.48052=2,280,960.1584
1 acre = 43,560 square feet1 acre 5 feet deep = 43,560 x 5 = 217,800 cubic feet = 1,629,257 gallons (rounded)