Calculate the volume (cubic ft capacity) of the pool and multiply by the number of gallons per cubic foot. To calculate, the formula is V = (Pi x R²)(H) where Pi = 3.1416, R² is the radius multiplied by itself (radius is one-half of the diameter), and H is the height or depth. There are 7.481 gallons of water in 1 cubic foot. V = (3.1416 x 12²)(4) = (3.1416 x 144)(4) = (242.3904)(4) = 1809.5616 cu ft 1809.5616 x 7.481 = 13,537.33 gallons
If the pond is uniformly 6-feet deep it would contain about 1,955,109 gallons of water.
A 25-acre pond that is uniformly 6 feet deep will hold about 48,877,714 gallons of water.
That all depends on how deep the 530 sq ft area is
Here is my take: 1 gallon of water equals 231 cubic inches 1 square foot, 1 inch tall equals 144 cubic inches (12"x12"X1") 1 square foot needs 0.624 gallons to equal 1 inch of cover (144 cubic inched divided by 231 cubic inches) 16 square feet would require 9.975 gallons of water to be covered 1 inch deep. (16*0.624) **Runsky**
There are 43,560 square feet in one acre. Water is often measured in gallons, and one cubic foot of water contains approximately 7.48 gallons. Therefore, one acre of water, to a depth of one foot, would contain about 325,851 gallons (43,560 square feet x 7.48 gallons per cubic foot).
1,770 gallons.
3,398.4 gallons.
6,200 gallons.
5,974 gallons.
Three feet of water in a 12-foot round pool is about 2,550 gallons.
About 5,310 gallons.
2,360 gallons.
About 19,355 gallons.
26,550 gallons.
9,440 gallons.
About 212 gallons.
About 13,010 gallons.