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There are (7 - 1)!/2 = 6!/2 = 360 of them.

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Q: How many possible Hamilton circuits exist in a graph with seven vertices?
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Vertices of triangular pyramid?

Yes, they do exist!


How many vertices does a vertices have?

None.Vertices is a plural term and therefore "a vertices" cannot exist. As a result "a vertices" cannot have any vertices. In fact, it cannot have anything apart from non-existence.


What is a shape that 6 faces and 9 vertices?

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How many vertices does a hexagon solid have?

There is no such thing as a hexagonal solid. A regular hexagon will tessellate and so it forms a plane (2-D) surface, not a 3-D shape.A 3-D shape with six faces is a hexahedron and this could be a triangular bipyramid with 5 vertices, a parallelepiped with 8 vertices, a pentagonal pyramid with six vertices. There are also other possible shapes.


What has 6 vertices and 15 edges?

I believe that such an object cannot exist in normal 3-d space. If there are 6 vertices, the maximum number of edges is 12.


A shape with 4 sides and three vertices?

A shape with four sides and three vertices does not exist in Euclidean geometry. In Euclidean geometry, a shape must have the same number of sides as vertices. Therefore, a shape with four sides would have four vertices.


Is it possible for convex polyhedron to have 6 faces 8 vertices and 10 edges?

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How many vertices edges and faces does a dodehedron have?

A dodehedron does not exist. A regular dodecahedron has 20 vertices, 30 edges and 12 faces. A dodecahedron must have 12 faces, but it can have any number from 8 to 20 vertices and so 18 to 30 edges.


How many judicial circuits exist in the federal system?

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What solid has 7 edges 4 vertices's and 4 edges that are the same?

The Euler characteristic indicates that such a solid does not exist.


Is it possible for lesbians to exist?

Of course lesbians exist. There are millions of them.


Does there exist a simple graph with 7 vertices having degrees 1 3 3 4 5 6 6?

No. Since the graph is simple, none of the vertices connect to themselves - that is, there are no arcs that loop back on themselves. Then the two vertices with degree 6 must connect to all the other vertices. Therefore there can be no vertex with less than two arcs [ to these two vertices]. So a vertex with degree 1 cannot be part of the graph.