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No, F + V = E + 2That's Euler's polyhedron formula (or Theorem). For a normal 3-d polyhedron to exist it must conform to that equation.

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Q: Is it possible for convex polyhedron to have 6 faces 8 vertices and 10 edges?
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Related questions

If a convex polyhedron has 12 edges and 8 faces then how many vertices does it have?

It has 6 vertices.


What has 4 faces 9 edges 6 vertices?

There is no such convex polyhedron in normal geometries because it does not satisfy the Euler characteristic. That requires that Faces + Vertices = Edges + 2


How many faces if there is 16 vertices and 37 edges?

If the object is a convex polyhedron, then, by Euler's characteristics, it should have 23 faces.


How many edges and vertices in a polyhedron?

The number of edges and vertices ina polyhedron will depend on the polyhedron one selects either to study, build or etc...


A polyhedron with 12 vertices and 30 edges has how many faces?

A polyhedron has 30 edges and 12 vertices. How many faces does it have


What polyhedron have some a face but no edges and no vertices?

A polyhedron must have at least 4 faces, at least 4 vertices and at least 6 edges.


What 3d shape has 4 faces 8 edges and 5 vertices?

The numbers in the question do not satisfy the Euler characteristic so there cannot be such a [convex] polyhedron.


Larissa made a model of of a polyhedron using 8 pieces of clay for vertices and 18 straws for the edges what type of polyhedron did Larissa make?

This polyhedron has 7 vertices and 12 edges.


What shape has 6 faces 10 vertices's 15 edges?

I believe you intend to talk about a polyhedron if it is a convex polyhedron, there is a relation : F + V * E = 2 (you can experiment with current polyhedrons) the relation is not satisfied by your numbers


What do edges and vertices have in relation?

Edges join two vertices. Three or more edges meet at a vertex (it could be two if not in a polyhedron).


Euler's rule for a polyhedron?

For a simply connected polyhedron,Faces + Vertices = Edges + 2


What shape has 5 edges 9 faces and 6 vertices?

There can be no such convex polyhedron since the numbers do not satisfy the Euler characteristic which states that V - E + F = 2