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What is the sum of the measures of the interior angles of a polygon with twelve sides?
The interior angles add up to 1800 degrees
What is the interior angle sum of a 12 sided polygon?
1800 degrees. (Number of sides - 2) x 180 = (12 -2) x 180 =10 x 180 = 1800
What are the degrees of a 12 sided polygon?
To get the degrees of a polygon, we first need to figure out the total amount of degrees in the polygon. I'm assuming that you want interior angles. To figure out the number of degrees in a polygon, take the number of sides, subtract two from it, and then multiply by 180. So for a 12 sided polygon, there would be 1800 degrees total in the polygon. Now we need to find the amount of degrees in each angle. To do that, divide the 1800 that we just got by 12, and you get 150. So that means that each angle (assuming all the angles are congruent) will be 150o.
What type of polygon carries a total angle of 1800 degrees?
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When a convex polygon has 12 sides what is the sum of the measures of the interior angles?
To find the sum of the interior angles of a convex 12-sided polygon, you use the formula (n-2)180 n being the number of sides Therefore, (12-2)180 = 10(180) = 1800 degrees So the sum is 1800 degrees I believe this is right, but please correct me if I am wrong.
