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How many square inches in an 8 circle?

Updated: 4/28/2022
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14y ago

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8" circle = 50.26548 sq. "

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14y ago
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Q: How many square inches in an 8 circle?
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Related questions

How many square inches are there in a 8 inch circle?

The area of a circle with an 8 inch diameter is approximately 50.27 square inches.


What is the area of an 8 inch circle?

If the circle has a diameter of 8 inches, it's 50.265 square inches. If the circle has a radius of 8 inches, it's 201.06193 square inches. In the odd case that the circle has a circumference of 8 inches, it's 5.09296 square inches.


How many square inches are in 8 inches diameter circle?

There are: pi*42 = 50.265 square inches rounded to three decimal places


How many square inches in a 8 diameter circle?

Area = pi*42 = 50.265 square inches to 3 decimal places


What equation can be used to find the area in square inches of a circle with a radius of 8 inches?

Area of the circle in square inches = pi*82


What is the area of a circle with an 8 inch diameter?

The area of a circle with an 8 inch diameter is: 50.27 square inches. There are: pi*4 squared = 16*pi square inches or about 50 square inches


How many square inches in a 8 inch diameter circle?

Area = pi*42 = 50.265 square inches to 3 decimal places


What is the area of a circle with a diameter of 8 in?

The area of a circle with a diameter of 8 inches is: 50.27 square inches.


How many square inches are in a 16 circle?

The area of a circle is πr2 where π=3.14159 (approx) and r = radius of the circle. So 3.14159 x 8 x 8 = 201.06193 square inches.


What is the area of a circle with diameter of 8 inches?

diameter = 8 inches so the radius will = 4 inches area of a circle = pi*radius2 area = 50.26548246 or 50 square inches to the nearest square inch.


How many square inches are in 16 inches diameter circle?

Area of a circle = pi R2R = radius = 1/2 diameter.For diameter = 16 inches, Area = pi (8)2 = 64 pi = 201.1 square inches (rounded)


What is the radius of a circle with a diameter of 8 in?

50.27 square inches.