Missing information. The rectangle could be a square then the two sides would be the square root of 5000 or about 70.71. As the rectangle gets longer the sides change and thus the dimensions.
26.4 inches for the diagonal.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.
44 feet 4 inches
The diagonal of a rectangle is the third and longest side of a triangle with sides the same as those of the rectangle, so its length is the square root of the sum of the squares of the lengths of the sides of the triangle, (Pythoagoras' Theorem) which are also the sides of the rectangle. If the rectangle is 3 inches by 4 inches, then the diagonal is the square root of 3 squared (= 9) and 4 squared (= 16) so the diagonal is the square root of 16 + 9 = 25, giving it the length of 5 inches.
26.4 inches for the diagonal.
The diagonal is 221.2 inches long.
157.6102789 inches
15 and 20 inches because these dimensions comply with Pythagoras' theorem and the area of the rectangle.
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
You use the pythagorous theorm to calculate the hypotenuse of the triangle, which is the same line as the diagonal. 7(7)+ 10(10)= diagonal x diagonal 149= diagonal x diagonal Diagonal= square root of 149: this approximates to 12.207in Visit quickanswerz.com for more math help/tutoring! Consider a rectangle with dimensions 7 inches by 10 inches. Let ABCD be the rectangle. We need to find the length of the diagonal. We know that the diagonals of a rectangle are same in length. So, it is enough to find the length of the diagonal BD. From the rectangle ABCD, it is clear that the triangle BCD is a right angled triangle. So, we can find the length of the diagonal using the Pythagorean Theorem. BD2 = BC2 + DC2 BD2 = 102 + 72 BD2 = 100 + 49 BD2 = 149 BD = √149 BD = 12.207 So, the length of the diagonal is 12.21 inches. Source: www.icoachmath.com
The dimensions of the rectangle are 3 inches by 14 inches
Any rectangle that measures 12-in x 13-in has a diagonal ofsqrt(122 + 132) = 17.692 inches (rounded)
diagonal is 13 inch length of the rectangle of 12 and 5 inches sides
The diagonal length is about 18.44 inches.
The square of the diagonal is (652+692)=8986 The diagonal is then the square root of 8986=94.79...