You use the pythagorous theorm to calculate the hypotenuse of the triangle, which is the same line as the diagonal. 7(7)+ 10(10)= diagonal x diagonal 149= diagonal x diagonal Diagonal= square root of 149: this approximates to 12.207in Visit quickanswerz.com for more math help/tutoring!
Consider a rectangle with dimensions 7 inches by 10 inches. Let ABCD be the rectangle. We need to find the length of the diagonal. We know that the diagonals of a rectangle are same in length. So, it is enough to find the length of the diagonal BD. From the rectangle ABCD, it is clear that the triangle BCD is a right angled triangle. So, we can find the length of the diagonal using the Pythagorean Theorem. BD2 = BC2 + DC2 BD2 = 102 + 72 BD2 = 100 + 49 BD2 = 149 BD = √149 BD = 12.207 So, the length of the diagonal is 12.21 inches. Source: www.icoachmath.com
The diagonal is 221.2 inches long.
The diagonal is 100'
The diagonal is 47.707'
26.4 inches for the diagonal.
157.6102789 inches
152feet 3.79inches (rounded)
20 ft
134.6 feet
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
By Pythagoras, the length of the diagonal = sqrt[(1.8)2 + (1.2)2] = sqrt[3.24 + 1.44] = sqrt[4.68] = 2.16 m
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft
The diagonal is 15.652'