The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
X^2+y^2=8^2
i took the quiz
(x-1)^2 + (y-2)^2 = 3^2
11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2
4
9 (APEX)
x2/4^2+y2/12^2=1
x2 + y2 = 25
x2 + y2= 16
x2 + y2 = 25
x2 + y2 = 36
x2 + y2 = 49
x2 + y2 = r2, the equation of a circle centered at the origin. If you want to make the circle larger, increase the radius length.
Since the circle is centered at the origin, the equation of the circle is x2 + y2 = r2. So we have: x2 + y2 = (3/2)2 x2 + y2 = 9/4
Equation of circle: (x+2)^2 +(y+3) = 49
Equation of circle: (x-3)^2 +(y-2)^2 = 49
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
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