The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
(x-1)^2 + (y-2)^2 = 3^2
11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2
4
9 (APEX)
x2/4^2+y2/12^2=1
x2 + y2 = 25
x2 + y2= 16
x2 + y2 = 25
x2 + y2 = 36
x2 + y2 = 49
Since the circle is centered at the origin, the equation of the circle is x2 + y2 = r2. So we have: x2 + y2 = (3/2)2 x2 + y2 = 9/4
Equation of circle: (x+2)^2 +(y+3) = 49
1.6667
Equation of circle: (x-3)^2 +(y-2)^2 = 49
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
Equation: (x+1)^2 +(y-3)^2 = 16