Perimeter=2(l+b) =2*6 =12m
The area of a rectangle is its Length times its Width. For the question, we first need to make sure that the Length and Width share the same units: Length = 2m Width = 16cm = 0.16m Now we can safely calculate the area: Area = Length x Width = 2 x 0.16 = 0.32 square meters
Assuming that you are determining the surface area of a rectangle, in order to perform the calculation you would multiply the length (10m) by the width (2m):Surface Area = Length x WidthSurface Area = 10m x 2mSurface Area = 20m^2
This is a rectangle, not a square, but the problem is solved in the same manner. Multiply length x width. You did not provide units for the 2 and 7, so I'll give you some answers with various units. If the units for length and width are centimeters, A = 2cm x 7cm = 14cm2. If the units for length and width are meters, A = 2m x 7m = 14m2. If the units for length and width are inches, A = 2in x 7in = 14in2. If the units for length and width are feet, A = 2ft x 7ft = 14ft2.
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A rectangle is one of the six faces of a cuboid (a rectangular parallelepiped). The area of a rectangle 4m long and 2m wide is 8m2. Multiply this by the thickness (or depth) of the cuboid to obtain its volume.
Length = 20 m and width = 9 m
32m2 = 2m x 16m(width)Length(a) x width (16m) = 288m2288m2 / 16m = 18m
P = 130, so L + W = 65. 65 - 2 = 63, 63/3 = 21 m which is the width, making the length 21 + 21 + 2 ie 44 m
Let the width be 1/2x+2 and the length be x: 2(width+length) = perimeter 2(1/2x+2+x) = 97m x+4+2x = 97 x+2x = 97-4 3x = 93 x = 31 Therefore: length = 31m and width = 17.5m Check: 31+31+17.5+17.5 = 97m
Perimeter of a rectangle is 2 times (length + width) P = 2 (L+W) In this case the length is 2m more than twice the width. That is written L = 2 + 2W P = 2 (L + W) 58 = 2 (2+ 2W + W) 58 = 2 (2 + 3W) 58/2 = (2(2+3W))/2 29 = 2 + 3W 29 - 2 = 2 + 3W - 2 27 = 3W 9 = W L = 2 + 2W L = 2 +2(9) L = 2 + 18 L = 20 For a rectangle with a perimeter of 58 m and a length that is 2 m more than twice the width, the length is 20 m and the width is 9 m.
1m and 11m 2m and 10m 3m and 9m 4m and 8m 5m and 7m. The next one, 6m and 6m, would be a square.
The area of a rectangle is its Length times its Width. For the question, we first need to make sure that the Length and Width share the same units: Length = 2m Width = 16cm = 0.16m Now we can safely calculate the area: Area = Length x Width = 2 x 0.16 = 0.32 square meters
Assuming the yard is rectangular then the following applies: The perimeter of a rectangle is the distance around the outside of the rectangle. A rectangle has four sides with opposite sides being congruent. The formula for finding the perimeter is Side A + Side B + Side A + Side B. This could also be stated as 2xSide A + 2xSide B or 2x(Side A + Side B) Side A =2m, p = 24m, therefore: 2x2m + 2xside B = 24m Side B = (24-4) ÷ 2 = 10m
Assuming that you are determining the surface area of a rectangle, in order to perform the calculation you would multiply the length (10m) by the width (2m):Surface Area = Length x WidthSurface Area = 10m x 2mSurface Area = 20m^2
This is a rectangle, not a square, but the problem is solved in the same manner. Multiply length x width. You did not provide units for the 2 and 7, so I'll give you some answers with various units. If the units for length and width are centimeters, A = 2cm x 7cm = 14cm2. If the units for length and width are meters, A = 2m x 7m = 14m2. If the units for length and width are inches, A = 2in x 7in = 14in2. If the units for length and width are feet, A = 2ft x 7ft = 14ft2.
Area = 2*0.9 = 1.8 square m
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