This is a rectangle, not a square, but the problem is solved in the same manner. Multiply length x width. You did not provide units for the 2 and 7, so I'll give you some answers with various units.
If the units for length and width are centimeters, A = 2cm x 7cm = 14cm2.
If the units for length and width are meters, A = 2m x 7m = 14m2.
If the units for length and width are inches, A = 2in x 7in = 14in2.
If the units for length and width are feet, A = 2ft x 7ft = 14ft2.
The area is 4x2 square units
Let length be 2x and the width be x and use Pythagoras' theorem: 2x2+x2 = 252 3x2 = 625 Divide both sides by 3 and then square root both sides: x = 14.43375673 cm 2x = 28.86751346 cm Area = 2x*x = 416 and 2/3 square cm
Say the radius of the circle is x. This makes the area of the circle pi x2. Since the length of the square's sides is the diameter of the circle, 2x, its area is 2x * 2x = 4x2. The percentage occupied by the circle is the area of the circle divided by the area of the square times 100 pi/4 x 100; pi/4 x 100 = 100pi/4 = 25pi = 78.6%.
The formula for finding the area of a rectcngle is: L * W = A Let x represent the width and 2x represent the length (twice the width). Set up the equation and solve: 2x * x = 50 (then simplify) 2x² = 50 (then divide both sides to find the value of x²) x² = 25 (then find the square root of 25 to solve for x) x = 5 the width (x) = 5, and the length (2x) = 10
a rectangle has a length of 2x-5 units and a width of x-3 units. what is the area, in square units, of the rectangle?
The area is 4x2 square units
Let the width be 2x and the length be x: width*length = area 2x*x = 200 sq ft 2x2 = 200 Divide both sides by 2 and then square root both sides: x = 10 Therefore: length = 10 ft and width = 20 ft
Let length be 2x and the width be x and use Pythagoras' theorem: 2x2+x2 = 252 3x2 = 625 Divide both sides by 3 and then square root both sides: x = 14.43375673 cm 2x = 28.86751346 cm Area = 2x*x = 416 and 2/3 square cm
A = 2x(x - 2) = 2x2 - 4x
Say the radius of the circle is x. This makes the area of the circle pi x2. Since the length of the square's sides is the diameter of the circle, 2x, its area is 2x * 2x = 4x2. The percentage occupied by the circle is the area of the circle divided by the area of the square times 100 pi/4 x 100; pi/4 x 100 = 100pi/4 = 25pi = 78.6%.
The perimeter is the sum of the sides. So if a square has a side of length 1, its perimeter is 1+1+1=1 = 4 If a square has a side doubled to length 2, its perimeter is 2+2+2+2 = 8, or double what it was before. Mathematically, if each side is length x it perimeter is x + x + x = X = 4x If each side is length 2x, its perimeter is 2x +2x+2x+2x = 8x
3
The formula for finding the area of a rectcngle is: L * W = A Let x represent the width and 2x represent the length (twice the width). Set up the equation and solve: 2x * x = 50 (then simplify) 2x² = 50 (then divide both sides to find the value of x²) x² = 25 (then find the square root of 25 to solve for x) x = 5 the width (x) = 5, and the length (2x) = 10
4(2x+3) [there's 4 equal sides] 4(2x)+4(3) 8x+12
a rectangle has a length of 2x-5 units and a width of x-3 units. what is the area, in square units, of the rectangle?
The question is not quite clear in what's it's asking. Presumably it's asking what is the length and width of the rectangle? Let the length be 2x and the width be x: 2x*x = 18 2x2 = 18 Divide both sides by 2: x2 = 9 Square root both sides: x = 3 Therefore: length = 6 inches and width = 3 inches If it is asking what the width is, and the length is twice the area, then the width would be .5 inches. (L= A*2, L=36) (36*.5=18) (L*W=A)
Let the width = X. The length is twice the width plus 5. So the length must be 2X + 5. Area = 63 ft squared = X multiplied by 2X + 5 = 2X squared + 25. 2X squared = 63 - 25 = 38 2X = square root of 38. Therefore the width is the square root of 38 divided by 2 and the length is the square root of 38 plus 5.