Well, darling, let me break it down for you. If point O is inside quadrilateral ABCD, then the sum of the distances from point O to each of the four sides of the quadrilateral is equal to the sum of the diagonals AC and BD. It's a little math magic that shows O is cozy in the middle of the quadrilateral, no matter which way you slice it.
a and d
never
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What is ABCD? It is a quadrilateral, but what it is? What is 3x - 7? A side, a perimeter, or what else? Please, give me some additional information in order to be able to solve this problem.
A rectangle.
You cannot prove it since it is not true for a general quadrilateral.
none of these answers are correct
This is the image
To prove that quadrilateral ABCD is a parallelogram, you need to establish one of the following conditions: either both pairs of opposite sides are parallel, both pairs of opposite sides are equal in length, or one pair of opposite sides is both equal and parallel. Alternatively, showing that the diagonals bisect each other or that one pair of opposite angles are equal can also suffice. Any of these conditions will confirm that ABCD is a parallelogram.
A quadrilateral is a parallelogram if one pair of opposite sides are equal and parallel Let ABCD be a quadrilateral in which ABCD and AB=CD, where means parallel to. Construct line AC and create triangles ABC and ADC. Now, in triangles ABC and ADC, AB=CD (given) AC = AC (common side) Angle BAC=Angle ACD (corresponding parts of corresponding triangles or CPCTC) Triangle ABC is congruent to triangle CDA by Side Angle Side Angle BCA =Angle DAC by CPCTC And since these are alternate angles, ADBC. Thus in the quadrilateral ABCD, ABCD and ADBC. We conclude ABCD is a parallelogram. var content_characters_counter = '1032';
Since E is inside square ABCD and X is on side CD, then EX must be less than EY since X is closer to the interior of the square. Since EY crosses side AD and E is inside ABCD, it proves that E must lie on side BD as only one point could be both on BD and inside ABCD.
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a and d
never
never
"abcd is not a parallelogram or it does not have any right angles." ~(P and Q) = ~P or ~Q
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