equation for any regular polygon when n = number of sides: 180(n-2)/n
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 166.15 degrees
Sum of the interior angles of a n-gon = (n-2)*180 degrees. So, for a polygon with 20 sides, the sum og the 20 interior angles is (20-2)*180 = 18*180 = 3240 degrees. Since it is a regular polygon, all interior angles are equal, and each one is 3240/20 degrees = 162 degrees.
There is no way to work out the angles in a general polygon. The sum of the interior angles of a polygon, with n sides, is (n-2)*pi radians [or (n-2)*180 degrees]. Therefore, if you know the measure of n-1 angles, you can work out the size of the nth angle.Alternatively, if the polygon is one of the rare type - a regular polygon - then all its angles are equal. In that case, you can divided the above sum by n.
Providing that it is a regular 35-agon then its interior angles add up to 5940 degrees and each interior angle is 5940/35 = 169.'714285' degrees recurring decimal '714285'
Each interior angle is: 1520 18' 27.69''
this depends on what type of polygon it is.. if it is a regular triangle, then all interior angles measure up to 180 degrees. So, a triangles interior angles would measure 60 degrees each.
Exterior angles are supplementary with interior angles, so 180-30=150
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 166.15 degrees
Exterior angles are 7.5 There are 48 sides.
Each individual interior angle will measure 160 degrees
Sum of the interior angles of a n-gon = (n-2)*180 degrees. So, for a polygon with 20 sides, the sum og the 20 interior angles is (20-2)*180 = 18*180 = 3240 degrees. Since it is a regular polygon, all interior angles are equal, and each one is 3240/20 degrees = 162 degrees.
The sum of the interior angles of a n-gon is (n-2)*180 degrees. So the sum of the interior angles of a heptagon is (7-2)*180 degrees = 5*180 = 900 degrees.Since it is a regular polygon, each of its interior angles is the same and so each is 900/7 = 128.571428 degrees.
No. The total of the interior angles of a polygon is given by: total_of_interior_angles = 180° × (number_of_sides -2) A regular polygon has every interior angle the same, and the size of each angle is given by: size_of_interior_angle = total_of_interior_angles / number_of_sides → size_of_interior_angle = 180° × (number_of_sides -2) / number_of_sides But as number_of_sides - 2 is (always) less than number_of_sides, (number_of_sides -2) / number_of_sides is less than 1 and so the size_of_interior_angle is less than 180°. To be a concave polygon, at least one interior angle must be greater than 180°. But as a regular polygon has all interior angles less than 180°, no regular polygon can be concave.
152.307692 repeating degrees
108 degrees The sum of all interior angles of a polygon is equal to the following: 180n-360, where n is the number of sides. For n=5, the total of all of the angles is 180*5-360=900-360=540. Since every angle in a regular polygon, each interior angle of a regular pentagon is 540/5=108 degrees.
If its a regular polygon then its 147 degrees.
No. The sum of the exterior angles of a polygon sum to 360o For a regular polygon, they are all the same size ⇒ dividing 360o by the exterior angle gives the number of sides. Interior angle = 154o ⇒ exterior angle = 180o - 154o = 26o ⇒ number of sides = 360o ÷ 26o = 1311/13 sides But a polygon must have a whole number of sides ⇒ 154o cannot be the interior angle of a regular polygon.