Are perpendicular.
Slopes of parallel lines have the same slope (they are changing at the same rate).Slopes of perpendicular lines have slopes that are the negative inverse of each other, that is, their product is -1. (The slope of a vertical line is therefore undetermined, not infinity. There is no slope s that times 0 equals -1.)---Let m1 be the slope of line one and m2 be the slope of line two. Then:If the lines are parallel, then their slopes are equal, so m1 - m2 = 0.If the lines are perpendicular, then their slopes are negative inverses of each other, so= m1 - (-1/m1)= m1 + 1/m1= (m12 + 1)/m1
Negative reciprocal slopes always represent perpendicular lines.
It is always -1.
true (APEX)
true (APEX)
If the lines are perpendicular, their slopes are negative reciprocals.If the lines are perpendicular, their slopes are negative reciprocals.If the lines are perpendicular, their slopes are negative reciprocals.If the lines are perpendicular, their slopes are negative reciprocals.
Are perpendicular to one another.
Two numbers are negative reciprocals if their product is -1. The numbers 1/2 and -2 are negative reciprocals. Their product is -1. This is often seen in problems involving the slopes of two lines. The slopes of perpendicular lines are negative reciprocals. Their product is -1.
negative reciprocal slopes ---> the lines are perpendicular equal slopes ---> the lines are parallel
I believe they have Negative Slopes as stated by my Geometry Book. "Perpendicular Lines Have Slopes Which Are Negative ___"
You have to know the slopes of both lines. -- Take the two slopes. -- The lines are perpendicular if (one slope) = -1/(the other slope), or the product of the slopes equals to -1.
Perpendicular
Slopes of parallel lines have the same slope (they are changing at the same rate).Slopes of perpendicular lines have slopes that are the negative inverse of each other, that is, their product is -1. (The slope of a vertical line is therefore undetermined, not infinity. There is no slope s that times 0 equals -1.)---Let m1 be the slope of line one and m2 be the slope of line two. Then:If the lines are parallel, then their slopes are equal, so m1 - m2 = 0.If the lines are perpendicular, then their slopes are negative inverses of each other, so= m1 - (-1/m1)= m1 + 1/m1= (m12 + 1)/m1
One is the negative reciprocal of the other. That is, the product of the two slopes is -1. UNLESS one of them is zero, in which case the slope of the other is infinite.
If the product is -1 then the lines are perpendicular to one another.
Negative reciprocal slopes always represent perpendicular lines.
Yes, as long as the negative slopes are both equal.