sum of exterior angles in a polygon is always equal to 3600,
sum of all the interior angles is given by (n-2)1800, where n is the number of sides of the polygon.
According to the question,
answer:6
1 a circle 360 interior angles 360 exterior agles
Hint: in a regular polygon interior plus exterior = 180o, always.
If you multiply 360 by the number of angles in the polygon and then subtract the sum of all the interior angles you will end up with the sum of all the exterior angles of the polygon.
A 4 sided quadrilateral has interior angles that add up to 360 degrees and its exterior angles add up to 360 degrees
540 degrees
1 a circle 360 interior angles 360 exterior agles
Hint: in a regular polygon interior plus exterior = 180o, always.
If you multiply 360 by the number of angles in the polygon and then subtract the sum of all the interior angles you will end up with the sum of all the exterior angles of the polygon.
If exterior angles are 120 then interior angles must be 60 so you have an equilateral triangle
A 4 sided quadrilateral has interior angles that add up to 360 degrees and its exterior angles add up to 360 degrees
360
The sum of a regular polygon's interior angles is always equal to (n-2) * 180, where n is the number of sides in the polygon. Given that one exterior angle measures 40 degrees, we can find the interior angle by subtracting 40 from 180 degrees (since the exterior and interior angles are supplementary) to get 140 degrees. So, the sum of the interior angles of the regular polygon is 140 * n.
540 degrees
The total of the interior angles equal 5040, and each angle measures 168 degrees The total of the exterior angles equal 360, and each angle measures 12 degrees
There are 5 interior angles and each one measures 108 degrees (180-72). Since the sum of exterior angles of any polygon is 360⁰, then that polygon would have 5 angles (360/72). So the sum of interior angle measures is 540⁰.
The 3 interior angles of this equilateral triangle will add up to 180 degrees
360 degees